<p>Ohh the one with the 5th term was 10</p>
<p>It was 3 times. I did it in like 20-30 seconds because it was one of the the last problems I went back to do. I just plugged in values for each and did the area formulas for both.</p>
<p>you are wrong Girligrl22
triangle= (1/2).(x/2).x = (1/4)x^2
trapezoid= ((x+x/2)/2 ).x= (3/4)x^2</p>
<p>r=3</p>
<p>We will agree to disagree <3
What other qs did yall think were difficult</p>
<p>Girlygirl…
Do you really believe the answer is 4? If you plug in 5 as the side-length of the square, you get the total area as 25. Then since you are given the midpoint of one side, you can determine that the length of that midpoint is 2.5. So the triangle base is 2.5 and the height is 5. The formula for triangle area is 1/2bh, so you get the area for this as 6.25. If you subtract 6.25 from 25, you get 18.75, which is the area of the trapezoid. And now of you divide the area of the trapezoid by the area of the triangle (18.75/6.25) you get 3. Therefore, r=3. Not 4.</p>
<p>formulas for area:
Triangle: (1/2)base.height
Trapezoid: (base1 + base 2)/2 . height</p>
<p>Take a look them. It is 3. If you know this formulas maybe you misread the directions.</p>
<p>
Actually it’s the rectangle that could fit 4 congruent right triangles; trapezoid consists of 3.</p>
<p>i got 3 for that and am sure of it:D</p>
<p>wat was the answer to 50th question? wat raw score can make it to 550 scale score</p>
<p>Any ideas on how the curve will be?</p>
<p>I answered the 50th already. The answer is all real numbers except 5.</p>
<p>Sin and cos answer was all reals</p>
<p>are you talking about that question sin2(sin) cos2(…) something like that</p>
<p>Anybody check their scores?</p>