<p>Are you guys sure that the P one was P is odd and >3? I remember I plugged in 2 and got 3… but I was braindead so I might’ve plugged it in wrong.</p>
<p>Also, what was the one with the unit circle with center O?</p>
<p>@wisdom908: I did…</p>
<p>about the P problem, I think the question stipulated that n>2</p>
<p>I disagree that the periodic function one was 2. If the function isn’t a continuous curve, how can it have a period? There were merely points, not lines.</p>
<p>I thought that P > 3 and odd? Or is that the same question?</p>
<p>So, do they decide the curve after or before the test is given?</p>
<p>wait wasnt that one y-x = 6?</p>
<p>hmm… i thought the p problem said that n>1 and n was an integer</p>
<p>Vouloir, I think you plugged it in wrong. I plugged 2 in and got an odd. (In fact I think plugging in 2 gave you 3)</p>
<p>@hello, the line that passes through the two points is y-x=6, the line that’s equidistant is y+x=6</p>
<p>@chloeee: Are you sure? I could’ve sworn it was n > 1. </p>
<p>What do you guys expect the curve on this test to be? -6 as usual? (For 800)</p>
<p>@WhartonKid: A periodic function is a function that repeats its values in regular intervals or periods. The only prerequisite is whether or not it IS a function. It doesn’t have to be a curve to repeat its values in regular intervals.</p>
<p>hellohelloo, Yes your right, thats what I chose :)</p>
<p>@wisdom: yes, plugging in 2 gave me 3. If it’s n > 1, then it’s P is odd. If it’s n > 2, then it’s P is odd and >3.</p>
<p>The P one is definitely just P is odd. It was 1 + n^(1-(-1)^n)/2. Plug in 1, you get P = 2. Also, the trapezoid one, wasn’t it 8.13, since they didn’t give you the x value of C or D, and the height was about 2.5?</p>
<p>The line equidistant from two points is the perpendicular bisector of the line segment connecting the points. You find the line that 1. goes through the segment’s midpoint and 2. that has a slope that is the negative reciprocal of the slope of the segment.</p>
<p>Finding the length of the line segment with end points (0, f(0)) and (pi/2, g(pi/2)) where f(t)=2sint, g(t)=cos(t/2)?</p>
<p>This question was the tipping point of my test anxiety. I tried to use the distance formula but I kept getting an answer that wasn’t in the choices… maybe I just misread something.</p>
<p>@Username: That is what I did, BUT I believe you had to find the EXACT value of the height, which would’ve given you a different answer. I got that one wrong. :(</p>
<p>@ahua: I used the distance formula and got the correct answer. You might’ve overlooked something.</p>
<p>i got destroyed from question 38 to 45</p>
<p>…Are we even allowed to talk about the test?</p>
<p>To: UsernameInvalid </p>
<p>The height of the trapezoid should be the y coordinate of 1.25 (=1/2 of 2.5=1/2 of the top base of the trapezoid). To find this y-coord you need to do 4-1.25^2=2.4375. I’m guessing you estimated the height from the diagram instead (and that’s why you got 2.5 instead of 2.4375). The area of the trapezoid is thus 1/2(2.4375)(2.5+4) = 7.92.</p>
<p>questions and answers
probability of the 5 distinct letters (out of 5) plus 5 distinct numbers (out of 10): (5!(10!))/5!
trapezoid area with bases are 4 and 2.5, height is 2.4375: 7.92.
distance between two people at the post office: around .2 something
which function has zeros at -1 and 2: the one with only (x+1)(x-2) in the numerator (not numerator and denominator), only I is answer choice
abs value question: no solutions exist
radian measure: (1, 5pi/3)
3x-4=0, 3x-4 also equals what: 17
volume of cone that has dimensions 3x that of a similar cone with V=15: 120 cm^3
f(2x)=3x^2, find f(g(x)): 3(2(g(x))^2
multiple of 3 and 6 but not 18: 24
recursively defined sequence given S2=2 and each term is 2(S(n-1)) : Sk=2^(k-1)
songwriter: .2(75+.15n)
chord of triangle length: sq root (2-2cosx)
limit as x approaches infinity: 2
long diagonal of rectangular solid: 9.7
least squares regression prediction: 190
exponential decay 18%: 9446
mean, median salary: mean increases
exponential function what is 1/f(x): A, graph that looks like (1/(2^x)
function for set of points equidistant from (-1,5) and (1,7): y+x=6
length of the line segment with end points (0, f(0)) and (pi/2, g(pi/2)) where f(t)=2sint, g(t)=cos(t/2): 1.72
probability of numbers 1-10 inclusive, pick two (put the first back in after picking), sum of the two is >5 : 0.9
**
no answers:**
period question: 2?
P question: P is odd and >3? or just odd</p>
<p>ahea: same happened here. at first I did (f(0), g(0)) and (f(pi/2), g(pi/2)) at first, and wasn’t getting the right answer. Then I realized I had it wrong…
Yes that problem took up too much valuable time -_-</p>