<p>Anyone remember the choices for the last area problem. I’m fairly certain that I put 7.something but I might have placed B which could have been 7.6 instead of ~7.9</p>
<p>So do you remember the choices or if there were two answer choices with 7?</p>
<p>questions and answers
probability of the 5 distinct letters (out of 5) plus 5 distinct numbers (out of 10): (5!(10!))/5!
trapezoid area with bases are 4 and 2.5, height is 2.4375: 7.92.
distance between two people at the post office: around .2 something
which function has zeros at -1 and 2: the one with only (x+1)(x-2) in the numerator (not numerator and denominator), only I is answer choice
abs value question: no solutions exist
radian measure: (1, 5pi/3)
P question: P is odd and >3
3x-4=0, 3x-4 also equals what: 17
volume of cone that has dimensions 3x that of a similar cone with V=15: 120 cm^3
f(2x)=3x^2, find f(g(x)): 3(2(g(x))^2
multiple of 3 and 6 but not 18: 24
recursively defined sequence given S2=2 and each term is 2(S(n-1)) : Sk=2^(k-1)
songwriter: .2(75+.15n)
chord of triangle length: sq root (2-2cosx)
limit as x approaches infinity: 2
long diagonal of rectangular solid: 9.7
least squares regression prediction: 190
exponential decay 18%: 9446
mean, median salary: mean increases
exponential function what is 1/f(x): A, graph that looks like (1/(2^x)
function for set of points equidistant from (-1,5) and (1,7): y+x=6
**
no answers:**
period question: 2?
probability of numbers 1-10 inclusive, pick two (put the first back in after picking), sum of the two is >5 : ?</p>
<p>Feel free to correct/repost as needed</p>
<p>recursively defined: Sk = 2^K</p>
<p>Why was the recursively defined 2^k…I put B which was something like 2^(k-1)
I remember S1 was 1 though…I think?</p>
<p>And for the exponential decay: It’s ~9445 right?</p>
<p>yeah chloes right</p>
<p>I said 2^(k-1) aswell, the first term was a 1 and the only way to get a 1 is by raising to a 0=(1-1).</p>
<p>Oh. I might have overlooked that. 
Was it S0= 1?
1,2,4,8,16
It seemed to pass a manual check, but I might have forgot the S1 term. Anyone else?</p>
<p>Alright, seems everyone else agrees. I overlooked that (it was a choice right?) . Not reading all the choice.</p>
<p>The equidistant problem from points (-1,5) and (1,7) was y+x=6</p>
<p>Does anyone know what the answer to the linear regression was? Also, do they do a different curve for each test, since most people thought this was hardish</p>
<p>Yes, they gave you S2=2 and each term 2(Sn-1)</p>
<p>y+x=6, just because it works for the points? Thats what i put :)</p>
<p>Edit: OH, that line is on the points, therefore distance equals 0 for both points</p>
<p>Check the compiled list for the linear regression</p>
<p>Recursively defined sequence: </p>
<p>I think the problem was something like </p>
<p>S1 = 1
Sn = 2(S(n-1))</p>
<p>S2=2(1)=2
S3=2(2)=4
S4=2(4)=8
S5=2(8)=16</p>
<p>so SK = 2^(K-1)?</p>
<p>username: 190
also i disagree with the P one, P is odd but its not P > 3, because when n = 2, P equals 3 and that answer choice did not have > or equal to 3, so i thought the answer is just P is odd</p>
<p>Ahua852, Yes, that is what I and a couple others put. I think we have reached a consensus.</p>
<p>I put 2^k. </p>
<p>Sent from my SAMSUNG-SGH-I997 using CC App</p>
<p>Candid: Any reason why? ;)</p>
<p>Oh ■■■ i’m doing the equidistant from (-1, 5) and (1,7) one…the equation of the line through those two points is y=x+6 so the equidistant should be perpendicular with the same y int…so y+x=6 as previously mentioned.<br>
It’s so easy in retrospect…</p>
<p>GAW CC makes me feel like a ■■■■■■.
Anyone else find this test increasingly time consuming and ran out of time?</p>