<p>For the one where two segments intersected at (6, 4) to essentially form a rectangle with the x and y axis. What did you put as c for y=x+c so that it would make the “rectangle” in to two equilateral pieces?</p>
<p>the painter question was 798</p>
<p>I graphed abs tan 2x and it wasn’t pi/2 for the period</p>
<p>yes it was pi/2 u probably had the wrong window but if u did [-pi/4, pi/4] u would have only seen one period of the function so it had to be that</p>
<p>No it wasn’t 798, because it was asking for walls and ceiling and that would include 2lw + 2lh + 2wh</p>
<p>Wow I thought the painter thing was the entire surface area. Wow only the ****ing roof and walls?</p>
<p>**** me</p>
<p>what are you saying there is only ONE ceiling and FOUR walls. your equation finds the floor also…</p>
<p>I got -12 for the x^2-y^2 question: they gave y-x = 6, so x^2-y^2=(x+y)(x-y)=-6(x+y)=72, so x+y = -12</p>
<p>I didnt include the floor and I still got 798…</p>
<p>The period wasn’t pi/2…</p>
<p>yea thats the right answer</p>
<p>Length and width could be for floor and ceiling, but every problem involving part of the surface area in Barron’s or Princeton Review includes everything</p>
<p>Mathew, are u 100% sure it said walls and ceiling? If so then we are both wrong :(</p>
<p>You do not find the period of a tan the way you find that of the sin and cos</p>
<p>The painter question was not 798</p>
<p>What’s the maximum you can miss/skip and still get a 700?</p>
<p>It depends on how many u got right
How many u skipped
How many u got wrong
Wrong and skip are not equal</p>
<p>I got 798 as well.
The four walls have a combined area of 15<em>8+15</em>8+18<em>8+18</em>8 = 528. The ceiling has a surface area of 15*18 which is 270. 528 + 270 is 798.</p>
<p>I’m scared 
please tell me the painter question wasn’t 798. I don’t even remember whether if asked for floor and ceiling or just total. I did the total QQ</p>
<p>For the one where two segments intersected at (6, 4) to essentially form a rectangle with the x and y axis. What did you put as c for y=x+c so that it would make the “rectangle” in to two equilateral pieces?</p>