October 6 SAT math

Test Preparation SAT Preparation
261

<p>AHA!</p>

<p>Here's one that really confused me, because I thought a lot of the choices were possible except the odd one:</p>

<p>Twice x is even, and half of y is also even. What's a possible product of x and y?</p>

<p>I put 48.</p>

262

<p>LMAO we just completely connected there</p>

263

<p>i got $14.7 to the CD one</p>

264

<p>It asked for the area of the RECTANGLE</p>

265

<p>
[quote]
It was a parabola that formed a triangle. But the triangle had legs of 9 and 1.5, so shouldnt it be 9*1.5/2 = 6.75?

[/quote]
</p>

<p>it was the area of the rectangle, not the triangle. so dividing by two was unnecessary.</p>

266

<p>aaa11223, that question wasnt on my test, so i think it's experimental</p>

267

<p>Classof08 let's hope WE are right. LOL</p>

268

<p>how many right triangles fit into a rectangle - can't remember dimensions.</p>

269

<p>Why The Hell Would They Ask For The Area Of A Rectangle And Draw A Triangle</p>

270

<p>andreaaa are you sure? :( where did Calssof08 and i get the triangle thing from?</p>

271

<p>was it asking for a ratio or an actual amount. because you could find the height that the volume of hte cone filled the cyinder up to</p>

272

<p>yeah they definatly drew a triangle >.< and I swear they wrote triangle too. Darn</p>

273

<p>bull - I did exactly what you did. It asked for the depth the cylinder would fill up to, which I assumed to be height.</p>

274

<p>
[quote]
Why The Hell Would They Ask For The Area Of A Rectangle And Draw A Triangle

[/quote]
</p>

<p>well, it was a rectangle, with the diagonal drawn. i am 100 percent sure.</p>

275

<p>was it wrong?</p>

276

<p>im pretty sure they asked what h was. I think it was 2?</p>

277

<p>They said rectangle. The reason people were thrown off was because they only gave 3 points. That was the trick.</p>

278

<p>You guys read way too much into the cylinder and cone question. You simply just go by the formulas.
1/3piR^2H and piR^2H. The cylinder obviously contains three times the volume of the cone since Pi, R and H are all constant. Therefore if the R were to remain the same, you only change the H. You get the volume of the cone by multiplying the height of the cylinder by 1/3. 6/3 = 2.</p>

279

<p>It Has To Be A Triangle! Please!</p>

280

<p>you find the volume of the cone thing
then you find the volume of the cylinder
then you subtract the two volume
the answer you get is in in^3 not in as they want you to put it in
then you plug in radius for volume of cylinder but leave h as variable
then you solve for h
thats what i did</p>