<p>Nowhere did it state that there was a 90 degree angle in that triangle… so the pythagorean theorem shouldn’t work…</p>
<p>However, I put the same answer as well…</p>
<p>I put sqrt(17).</p>
<p>In the earlier sections there was a question of about students who buy lunch, and something about the averages. It was a quite a bit to read. I ended up guessing. Wondering if anyone remembers the answer they put.</p>
<p>This math section was a *****. It was easy, but long problems …didn’t finish in time and guessed on 5 or 6 everything else was right pretty sure</p>
<p>You mean the question with 5 students that had 4 decrease their lunch money by two dollars and one that kept it the same? I believe it wanted the average after the change took place, so since they all originally used six dollars, and 4 lowered it to 4 dollars, and one kept it the same, I did: (4(4) + 6)/5 and got 4.40. Someone can verify that.</p>
<p>^yeahhhhhh</p>
<p>damn i put 4.80 haha. Oh well. I probably got around 4-5 wrong then. Im pretty sure 740 Math SAT is better than whatever Ill get this time.</p>
<p>For the triangle in a circle i figured the diameter is the longest side since its straight down the middle, then using pythagorean, even though it didnt say 90 degrees for anything, i got sqrt 15 for the chord…?</p>
<p>me too neshy, anyone concur? what was the answer to #59? E?</p>
<p>How’d you get sqrt(15)? Because I thought the diameter was 4 and the other length was 1, making it sqrt(4^2 and 1^2) = sqrt(17).</p>
<p>And 59 was E. Yes.</p>
<p>that would make it greater than 4…</p>
<p>Oh shoot, lol. I guess I’m wrong then. Damn it, my logic seemed sound at the time. I don’t know how I missed that.</p>
<p>i feel ya. but you think you the letter for #60 too? I put J</p>
<p>Right but the diameter is straight down the middle which means it would be the longest side so the hypotenuse. So it becomes c^2 - a^2 = b^2. 16-1=15 b=sqrt15</p>
<p>What did the folded circle become</p>
<p>A square i think it was choice A</p>
<p>I thought that the chord would be the same as the diameter since it made an isocolese triangle.</p>
<p>I put sq root of 15 because that comes out right under 4. The diameter has to be the longest line that the circle contains. Again estimation to the rescue. :)</p>
<p>I used logic. It couldn’t be 2 or 3 bc one of the sides was 1 and 1+2 and 1+3 are not greater than 4. It couldn’t be 4 or rt17 bc it had to be shorter than the diameter. So it had to be rt15</p>
<p>I think I missed 3 or 4…I got the lunch one wrong because I was averaging it over both days and got 5.2 ( not an answer)…I think the sqrt 17 is wrong ( I sadly put that answer down)…the chord that the question asked us to solve wasn’t the hypotenuse…should be sqrt 15</p>
<p>59 was z3/8x^6y^9…if I remember question correctly…just had to take negative reciprocal</p>