<p>big b 14 try a few more examples and use 17/2 instead of 8</p>
<p>yeah i did the same thing... someone else seemed to do the same.</p>
<p>EDIT:im talking about the inequality one where ppl thought it was 32 but we put 62</p>
<p>What were the choices to the trapezoid one within the circles</p>
<p>so that's -2... damn.</p>
<p>the choices were</p>
<p>16
16+2sqrt3
16+4sqrt2
20
and something else... i dont remember, i think it as 24</p>
<p>Okay, for the one that was 6<square root on n<10, what was it? It wanted to know the maximum difference between the highest integer for n and the lowest.</p>
<p>the question that was
a[triangle]b =16; a+b =64</p>
<p>a was 34 right? o_o</p>
<p>was it 24 plus something or 24 cuz i might have put 24 down but i know I put a whole number.</p>
<p>Was their only one midpoint question.</p>
<p>root 37 and root 99 would be the greatest integers
so 6<root of (37 to 99) <100
so 99-37=62</p>
<p>daman i feel like we are talking about different problems... How am i supposed to "try" 17/2? it's not a question where you just plug in all the choices. Can you just explain how you solved it?</p>
<p>For the 5/8 answer, was it C? Because I'm not sure if I accidentally put 3/8 or actually circled 5/8. But I think my answer was C or E.</p>
<p>You can plug in numbers</p>
<p>put 2 for a and 1 for n
2^1=2
2^(1+4)=32, midpoint is 17
8.5*(2^1)=17</p>
<p>^ I got 62 (D). :]</p>
<p>yummymango - I got 5/8 too. I think the answer choice was D. It was right before 7/8 (E).</p>
<p>ok, i get it. thanks jmnd</p>
<p>I thought for the midpoint problem, n was 17/2. I could have sworn a bunch of people here said it was 17/2. </p>
<p>Xcellerator, do you remember what C was then?</p>
<p>The midpoint problem was 17/2.</p>
<p>yummymango - I don't really remember the other answer choices</p>
<p>Okay, I'm starting to get less confused. I thought there were two different midpoint problems.</p>
<p>Now you guys have depressed me, definantly one wrong. So what realistically do you think the lowest minus one could get me.</p>
<p>what about the one where you triple the equilateral triangle. was that the area of the 2nd triangle would be 9 times greater (C)?</p>
<p>-2... still hoping for a 760</p>