<p>i feel really bad for skipping 5 questions... i think i got rest of them right
i should have read the question more carefully</p>
<p>I thought that question was a trap, the one with the trapezoid and circles. However, I still put 20- the (Joe bloggs) answer.</p>
<p>For the perimeter question, look at ahtimmy's post (post 422).</p>
<p>Quick question,</p>
<p>what letter was answer 62 for 6<sqrtx<10?</p>
<p>D?
thanks</p>
<p>62 was D ...</p>
<p>what was the answer to the one where it gives you the arc and the triangle and you had to figure out the area of the shaded region...</p>
<p>i think i got like 9sqr2-6pi...i knew it was 6pi i just didn;t know if it was 18sqr or 9sqr...and somehow i got 9 but now not so sure anymore..</p>
<p>^ I got 18Sqr2-6pi.</p>
<p>that was C.
i think 18sq(3) - 6 pi , not 9</p>
<p>18(sqrt 2) - 6 pi</p>
<p>I think that's what I put</p>
<p>it was 18sqrt2-6pi</p>
<p>the triangle's sides were 6 and 6sqrt2
so the area is 18sqrt2.</p>
<p>the area of the circle is pi(6)^2
since it only covers 60 degrees, you have to divide by 6, which gives you 6pi.</p>
<p>so it as C? 18sqrt2-6pi</p>
<p>Akitorin...</p>
<p>Yes, that's the one I'm talking about.</p>
<p>I'm pretty sure it was 18sqr2 - 6pi but I rushed with that one since time was almost up.</p>
<p>@junshik</p>
<p>I thought it was a trick too at first, but I couldn't find justification for any other answer..</p>
<p>How did you come up with 18(sqrt 2)????</p>
<p>i thought the triangle was a 3-4-5....</p>
<p>I was confused and just skipped it....</p>
<p>same here 18 sqrt 2 - 6 pi</p>
<p>Did anyone here have the math experimental section, and do you have any idea which one it was?</p>
<p>I got 18sqrt2 - 6pi also. I did it sort of the "wrong" way but it worked out. I forgot how to calc the area of a part of a circle, so I just found the area of the equilateral triangle and it wasn't anywhere near 15pi...</p>
<p>I think the answer was 18root3 - 6pie for the shaded region question (3 4 5 triangle).</p>
<p>well i think i put 18 (sqrt 3) - 6pi cuz...</p>
<p>1) the degree measure was 60 degrees so its area is 1/6 that of the cirlce, and it has an area of 6 so the area of 1/6 cirlce is actually 6pi. and 6 is the leg of 60 degress so using 30-60-90 i got the area of the triangle .5<em>B</em>H which was 18sqrt3 and i subtracted 6pi from it to get the answer.</p>
<p>damn i got that one wrong and -f(x)=f(-x) i was just thinking that it was asking for an even equaction so i crossed off all of the odd equation...</p>
<p>other than that i think it was pretty good. </p>
<p>so 2 wrong for now...and probably 2 more just by stupid mistakes...so 690-770 according to the blue book...most likely 700...damn</p>
<p>and for the triangle arc one..i was using the law of sine or something...and i was confused and rushed.</p>