October SAT Math

<p>the hint was its a right triangle, 60 degrees, with a length 6, turn to the front page,, look at the given formulas...</p>

<p>??!!! law of sine!?! what ? no,i missed the -f(x)=f(-x) as well, i swear,if there were a section 11, or a section 10, with 1 min longer,i'd gotten this LOL</p>

<p>harvbound, 4 wrong can get u a 730 ish ONLY if u dont get penalized,if u do, that's 700</p>

<p>u still forgot the curve though right?</p>

<p>were both root 3 and root 2 choices?</p>

<p>i dont remember,but the only thing is 18sq(?)-6 pi. other ones were like 9 pi, 36 sq,12 sq ish, idk</p>

<p>-f(x) = f(-x) is just a even/odd function problem... the answer is x^3-x</p>

<p>it was definitely 18(sqrt 3)-6pi for this reason. </p>

<p>first off, it was a 60degree piece of the circle, so it's 1/6 * 36pi, everyone got that. nobody argues that it was 6pi for the slice of the circle right? </p>

<p>well if that's the case then it HAD to be 18 (sqrt 3) only because 9 (sqrt 3) - 6pi = a negative number. </p>

<p>that's how i figured it out at least.</p>

<p>Ren the SAT'er what do you mean penalized?...and yea i think so</p>

<p>Also, you guys know the "Figure not drawn to scale" problem, i think there was only one...anyway with two squares on a line? looked like a big diamond and a small dimond leaning on it? what was that? i put b=c because, where they "touch" that angle has to be 90 because they are ppdcular, so b would be 45 and c would be 45 also?...any comments?</p>

<p>I know that root 3 was correct. I'm just trying to remember whether I filled the right bubble.</p>

<p>Can anyone tell what exactly this question is asking for?
x^2+kx-10
25 + 5k - 10 = 0 then solve for k</p>

<p>I remeber this q, but I think I got 5 for some reason.</p>

<p>b=k and a=c (wasn't a choice)</p>

<p>look up transversal</p>

<p>also, how do u guys predict which section is experimental? if i had two CR's in a row, how r u able to say that Sec. 3 was experimental and not 2?</p>

<p>oh and sorry to double post but yeah, how come everyone thinks this curve is gonna be ridiculous like 1 wrong is a 500? yeah, most of the easy questions were REALLY easy, but it had it's fair share of difficult questions. i'm hoping this will be more of a standard curve cause i'm looking at maybe 2-3 wrong right now. if i don't improve over my 710 then i just wasted my friday night and i'mma be ****ed son</p>

<p>oh hostyoutube it was -3 for sure, i chkd on my graph. calc to be sure. i believe it was chocie "B"?</p>

<p>HarvardBound1123, if u got 4 wrong,then u would get -5 cuz penalty .25, however,if u only got -4 rawscore(maybe 2 omit 2 mc), that's -4 ,so this can make u go from 730 to 700 ish dependin on 4 or 5</p>

<p>the question was what does k equal</p>

<p>the answer was -3</p>

<p>ThisCouldBeHeaven in correct
it was b=k....because all others wouldnt work</p>

<p>1 omit so far!
For the last fill-in question I got 2 =(
My reasoning was:
16=(64)/(a+b)
Therefore, 16a+16b=64
Then I just put 2 for a.</p>

<p>Bleh... I guess cross-multiplying wouldn't have worked??</p>

<p>The answer to the area of the shaded region problem wasn't 18sqrt2-6pi, it was 18sqrt3-6pi since it was a 30-60-90 triangle. Since one side was 6, the other side opposite the hypotenuse had to be 6 sqrt 3. 6 times 6sqrt3 divided by 2= 18sqrt 3 and then you subtract 6 pi... so you come up with 18sqrt3 - 6pi...</p>

<p>your equation is right, but you would've had to factor out 16 and divide by 16... where did you get 2?</p>

<p>was there an option that was just 18sqr3?</p>