<p>I just know I’m going to be extremely disappointed if I don’t get a 5. I know a 4 is good too, but my chem teacher and a bunch of my friends have all been saying stuff like “Oh, you’ll get a 5. I’m sure” And I’ll just be upset if I don’t. </p>
<p>But I’m not afraid of blanking out. A little nervous that after an hour I’ll get too bored to keep taking it though</p>
<p>Same. I swear, I’m not that good with Chemistry and I’m lucky to get a 3 on this test. Not sure why I opted to take AP Chemistry.</p>
<p>I blanked out several tests for a few minutes and still finished in time so no. </p>
<p>And Tiny Chat lol? This is why we do group study with actual people not the internet chat services. And no this isn’t a group study even though there are people present here.</p>
<p>Very true. I’m just glad it at least won’t be as hard as the ACS Science Olympiad test.
But my teacher is making us do a lab after the AP exam for 11 days about Qualitative Analysis. -.-</p>
<p>I got a 5 on the 2008 practice exam under simulated AP Conditions without study (he made us take it cold!) but I was literally two composite points away from dropping down to the four range. I always underestimate myself and think I was just “lucky” with those FRQs</p>
<p>
Ditto. </p>
<p>Listen to this guy.</p>
<p>Ok when it say “The organic compound above” and choices are “organic acid; alcohol; ether; aldehyde; ketone”<br>
What does any of these mean (assuming the compound contains Carbons)?</p>
<p>i know that for this exam you are given a formula sheet. I also know that while doing practice ap’s that there are some equations not included such as a seperate density equation which i do not know? do you guys know of any other equation that are not included on the form sheet that are important to remember</p>
<p>t(1/2) = 0.693/k</p>
<p>That is the first order equation for calculating the half life. The k represents the rate constant!</p>
<p>@Descuff
Look at a table of organic functional groups.</p>
<p>This wasn’t my first experience with TinyChat but I (rather foolishly) assumed that this time might be better… It wasn’t. If anything, it was worse.
Can anyone explain to me (once and for all) what we need to know about vapor pressure and what factors affect it?</p>
<p>how to tell if delta G is negative or positive. i know its negative if the reaction is spont. but how do you tell?</p>
<p>Good luck on the AP test guys and give it your best effort~! Also don’t leave any questions blank, every point counts. Thank goodness they don’t take off points for wrong answers anymore lol. Anyway, shoot for 3+. I really hope I get 3 lol.</p>
<p>Vapor pressure is inversely proportional to the quantity of solute dissolved. The larger the van’t hoff factor, and the larger the number of moles of solute, causes a decrease in vapor pressure. Some of the solute occupies the surface of the system, which decreases the surface area available for the solvent to evaporate, decreasing the vapor pressure.</p>
<p>Temperature affects vapor pressure, since an increase in vapor pressure means that the intermolecular forces are weakened, and more molecules gain energy, making it more easy for the molecules to escape.</p>
<p>When is STP 273K and when is it 298K?</p>
<p>STP is always 273K</p>
<p>“how to tell if delta G is negative or positive. i know its negative if the reaction is spont. but how do you tell?”</p>
<p>delta G is defined as delta H - (kelvin temp)(delta S) </p>
<p>So basically you have to know delta H, delta S, and temperature (in Kelvins) and you can find delta G. </p>
<p>Although there are other formulas involving delta G that can tell you whether it is positive or negative, it depends on the time of problem.
For example, if it’s an redox reaction, the formula -(n)(Faraday)(E-cell) = delta G
Therefore, If E-cell is positive, delta G is negative, and vice-versa. </p>
<p>There is also a formula relating delta G and equilibrium constant, K, that can be used to determine delta G.</p>
<p>I’m off to bed. Good luck everyone! Shoot for a 5 so that you can land on at least a 3… 
Lol. Answer every question, don’t panic, write something down for every free response question even if you have no clue what it’s asking or whether it’s right, and most importantly, do your best. And hopefully you’ll be happy with the results come July!</p>
<p>Help. <a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>For number 1 f, I don’t get why the concentrations would be the same, shouldn’t be reversed?</p>
<p>@Trixzoh
If the concentrations were reversed, the value of K would be changed, which it shouldn’t. If the initial concentrations of reactant and product are reversed, the ratio of the concentrations (K) will still remain the same at equilibrium. Therefore, the equilibrium concentrations will remain the same as the ones previously calculated.</p>