<p>Yes and you have to interpret which i forgot to do</p>
<p>Yeah I put the T assumptions. I checked for outliers and skewness with the small sample</p>
<p>wow thats going to be like a 2/4 just for not showing conditions</p>
<p>what were all the answers to 2, a. not everyone is represented at the football game b. 000001-70000 alphabetical and no repeat c. different genders could drastically have different opinions</p>
<p>[3dd83</a> - Tinychat](<a href=“Live video chat rooms, simple and easy. - Tinychat”>Live video chat rooms, simple and easy. - Tinychat) </p>
<p>join so we can discuss</p>
<p>I said the two campuses could look different and the students at each could have varying opinions. Is tinychat only a paid app on IPhones or am I missing something?</p>
<p>A regression line does not need to go through the mean. Besides, the point that was an option was (y-bar, x-bar) which isn’t even a correct ordered pair option that makes sense…</p>
<p>And there was definitely an association between age and consumption… Look at the proportions… It’s a huge sample size, guys</p>
<p>Ugh… I totally did not read the directions to place the mean value into the chart AND plotting the point on the graph for number 6. I feel so stupid for making this mistake. It was basically giving free points.</p>
<p>I also did a&b by describing the graph using DOFS and SOCS… Also, I TOTALLY overlooked part D and continued with E… I think I did well though. The chi-sq and the Crows questions were the easiest FRQ’s though… Haha</p>
<p>What did everyone get as their chi-squared statistic and p-val? I got a very high statistic (up in the 600s) so I may have made a computational error, however I still think that the p val was statistically significant at the 5% level so we rejected the null and there was an association. Just curious as to what others got.</p>
<p>I don’t remember my pvalue… it was something like .011 and I rejected the null… did you calculate by hand or did the x2 test in the calculator and show the work?</p>
<p>everything by hand. even the table of expected values and the whole summation calculation. so I dont think its that big of a deal if I made a computation error. but bottom line, there was an association.</p>
<p>That must’ve taken you forever to do… Haha. How did you do 3) A ?</p>
<p>You didn’t show your work for the association test?? and 3A I justed calculated the z statistic (x-bar - u)/s and then found the p-value for greater than. so (850-840)/(7.9/sqroot(12))</p>
<p>You just use the Matrix thing on your calc for expected values… and my teacher said we only have to write out the (observed-expected)^2/expected for two values and add an ellipsis. then just write the test statistic.</p>
<p>this was my teachers first year of teaching the course so he just told us to do everything to be safe and whattnot tbh I dont even know how to use the “matrix thing” or what an “ellipsis” is lol</p>
<p>You go 2nd Matrix on your calc, edit, plug in the values from the chart that don’t include the totals. Then, you go to Stats, Tests, Chi-squared enter . Then go back to 2nd Matrix and click on B and it gives you the expected values.
and an ellipsis is just the “…” so the reader knows you continued the whole summation process. Doing the whole thing by hand is too time-consuming so my teacher only told us to write it out for two values and add the “…” since the calculator gives you the values once you run the chi-squared test.</p>
<p>Same here. For the egg one with the part A standardizing, did you have to divide by root n? Too bad I didn’t. Also slightly messed up on the SD of the single egg. Expecting a P, E, and P on the three parts of the question.</p>
<p>well i think i divided by root 12 because it was a sample where n=12 and s= (sigma/root(n))</p>
<p>and thanks for the break down I just emailed my teacher the process I found online so maybe he can implement it in next years course</p>
<p>Noproblem. 
I think I also divided by root 12. I wonder how the curve will turn out for this exam since it was easy for just about everyone.</p>