Official January 2013 International Math Discussion

<p>I guess we’re supposed to get the difference like for example in 2001 it was 1600 and in 2002 it was 1700 so there are 100 new students enrolled in 1 year</p>

<p>Didn’t they ask us to find the average number of students enrolled per year?</p>

<p>Kyoto2289: the question was asking the average of all years not 2001</p>

<p>Yes the difference between the two averages</p>

<p>So every year will have 100 new students</p>

<p>so would be like number of students on line 1 / 5
will be equal to the number of students on line 2 /5 </p>

<p>it was 8500 if i remember 8500-8500 = 0 :p</p>

<p>you assumed that the number of students increase at constant rate ?</p>

<p>NO! :stuck_out_tongue:
From where did u get the 8500? :P</p>

<p>Yes i remember getting a 0 :)</p>

<p>From the graph
In 2001, there were 1600 students
In 2002, there were 1700
In 2003, 1800
In 2004, 1900
And in 2005, 2000</p>

<p>The sum of students in each line.</p>

<p>I got it 50 :/</p>

<p>@Kyoto2289: if so then the other line was in 2001 : 2000
2002: 1900
decreasing etc… lol both averages are equal</p>

<p>For the modulus question,did they ask us to find minimum or maximum value?</p>

<p>No on the other line each year, there were 50 new students only not 100</p>

<p>it’s surely 0, because the number of students are increasing at a steady pace, both of them, and their median is the same.</p>

<p>I got 60 for the triangle in the cylinder and I got 50 for the avg student increase thing. Not 0.</p>

<p>Finally someone got it 50 like me :D</p>

<p>Its 50, they asked for avg increase in students between the two schools per year… Not increase in students in the years…</p>

<p>Many people got 93 for the question of temperatures people… If 88 was one of the temperatures given in the six temperatures… 93 is possible.</p>