Official January 2013 International Math Discussion

Test Preparation SAT Preparation
161

<p>Another one: 15n. Someone who jogs 2 miles each day from Monday through Friday, and 5 miles on Saturday, and nothing on Sunday - how much does he run in n weeks? 15n.</p>

162

<p>yes 15n i guess… it should be that…</p>

163

<p>@2200andbeyondXD What about the point not on the graph and the x + k and kx one? They were very easy anyway, so we can say we have 53/54. 54th one was probably easy too.</p>

<p>So I have 2 wrong (1 remainder and 5 workers - took a guess on each) and 3 omitted (includes 1 wrong grid-in (ice cream) and the ones I ran out of time for: (x-y)^2>0 and 10r=p (last one)).</p>

<p>Raw score: 48. I just want 700+</p>

164

<p>" What about the point not on the graph and the x + k and kx one?" </p>

<p>which ones? I can’t remember anything of the sort :/</p>

165

<p>This is the Math curve apparently:</p>

<p>54 800
53 770
52 740
51 720
50 710
49 700</p>

166

<p>@2200andbeyondXD See my post above the 15n one.</p>

167

<p>Do anyone remember the questions for xz the smallest and c=0 when k=3</p>

168

<p>@333770, I totally don’t remember what I put for that one… but (2,7) doesn’t seem like the correct answer cuz 7=2(3)+1 ,… but again i am not sure if u remember the question right so…</p>

<p>as for "f(x) x+ k , g(x)=kx , answer was 6? " I don’t remember the graph and choices so… sorry!! </p>

<p>and good job on updating my post of answers… thanks… glad someone still cares over here… lol :D</p>

169

<p>@333770
I answered 15n, it is correct</p>

170

<p>@hopingforbetter
was this question an mcq or grid in?. I am afraid I missed this one and answered another in it’s place :S. maybe this is in the experimental?</p>

171

<p>what was the question for this one “c=0 when k=3” ?
and for “1520 is value of x” ?</p>

172

<p>@YomnaAyman For “1520 is the value of x”, refer to post #166.</p>

<p>@mohamedbhar yes that was a grid-in. That was not in the experimental section. Sorry.</p>

<p>@333770 15n is right.</p>

<p>@2200andbeyondXD “f(x) = x+k and g(x) = kx”: the answer is 6. As far as I remember, f(3)=6 was given and g(2) was asked.</p>

173

<p>I don’t remember the “f(x) = x+k and g(x) =k” question, so I’d be happy if someone can confirm/clear that one.</p>

174

<p>Which grid-in section was experimental?</p>

175

<hr>

176

<p>Can somebody explain two questions please: </p>

<p>1) the graph with a slope of 6/5 - How did you get 10.6? </p>

<p>2) the two set question: 2 was the only one that was on both wasn’t it? So the probability should be 1/5 shouldn’t it?</p>

177

<p>@333770: where did you get that curve from?</p>

178

<p>From the March 2010 scores <a href=“http://talk.collegeconfidential.com/sat-preparation/895510-march-2010-sat-results.html[/url]”>http://talk.collegeconfidential.com/sat-preparation/895510-march-2010-sat-results.html&lt;/a&gt;&lt;/p&gt;

<p>the curve WAS hard… :frowning: sadly, but surely… It will be… And that means my dreams of a “good” CR score are shattered… </p>

<p>hhhhh… did I mention I HATE collegeboard? Cuz I do, really. :/</p>

179

<p>There is no way we could’ve gotten a median of 93 for two reasons

  1. No number from the list was 93 and the only way we could’ve gotten 93 as a median in a list with an uneven number of numbers (7 in this case)
  2. If the unknown seventh value from the temperatures was indeed 93 it could never have been the median because it would’ve been the biggest value of all and you need to put the list in order before finding the median</p>

<p>I put 88</p>

180

<p>yeah i think that’s the answer… that’s what I put at least :D</p>