<p>I know it's been discussed, but the symbol problem...</p>
<p>the equation was a 0 b = ab^2 +a+b I SWEAR.</p>
<p>That would mean II doesn't work, but was that the original equation? I know when I plugged in numbers I squared the ab part. Was I on crack? (I bet u'll say yes, but I swear...)</p>
<p>EDIT: I think I'm wrong, but have no idea why I would do that.</p>
<p>Wasn't it just ab? Not ab^2?</p>
<p>oh that one! sry. I put I and II for that one. III had an extra x yeah, it was ab</p>
<p>it must have been ab, yet I think I did square it. Oh well, I hope that was my only miss.</p>
<p>it was : ab+a+b</p>
<p>anyone remember all the choices to the one that was like x^2= x + 6</p>
<p>i could have sworn x=-2 wasn't one of the choices</p>
<p>I spent about 5 minutes checking that question. Its I+II. In III, you get an extra "x" on one side. My friend checked it with numbers and got the same answer.</p>
<p>it was x=-2</p>
<p>the answer to the average problem with 7, 8.5, and 10 is all three.... real numbers, not integers, im almost positive</p>
<p>The answer was x^2>x. Since x=2,-3 or soemthing. Basically -1<x<1, x^2="">x.</x<1,></p>
<p>i think it was just I and II not the third one...</p>
<p>From someone that wishes the SAT was based on memorizing minute details....I can attest that it said real numbers. I looked at it a bunch of times and made 100% absolutely sure that 8.5 would work. </p>
<p>And the one with the a o b definitely had an extra x in the last one, so it was only 1 and II i believe.</p>
<p>It said real numbers. Just because it said real numbers doesn't mean it was easy because you still have to multiply the average by 7, then subtract the sum of the numbers they gave you from that number. THEN you have to check whether there are two numbers between 6 and 20 that would work. I, II, and III all work.</p>
<p>Am I correct ofr the x^2>x?</p>
<p>
[Quote]
The answer was x^2>x.
[/Quote]
</p>
<p>if it was greater than, then x<3 is the answer</p>
<p>I thought X=-2,3. So, x isnts less than three, its less than or equal to three. But x^2 is always greater than x.</p>
<p>No because x = 3 and -2, so it can't be less than 3, so x^2>x was the answer.</p>
<p>I agree with Halcoyn.</p>
<p>Halycon, why is it not easy if it said real numbers? you'd just need to make sure the two numbers were between 6 and 20 but with decimals allowed it would be too simple.</p>
<p>darn! there was also a q that was like 2^m cannot equal which of the following and one of them was like 2^m * 4^m. Right?</p>