<p>i put 30sqrt3 or 30sqrt2</p>
<p>so I’m hoping i picked the right one</p>
<p>the quadrilateral can be split into two respective triangles.
…
With that being said, the angles were 120 90 and 90…120 being the angle on the far LEFT of the quadrilateral.
360-120-90-90=60 degrees . So that angle is 60 degrees, the one on the top right.</p>
<p>Bisect the two angles with a line that goes straight through the 60 degree angle and the 120 degree angle. You have two 30 60 90 triangles.</p>
<p>The 30 degree angle faces the 60 side, and the 60 angle faces side TV.</p>
<p>That means that 60 root 3 has to be the answer.</p>
<p>@howmanyofme - I’m pretty sure it wasn’t 60sqrt3… it was bigger than the hypotenuse</p>
<p>or i might be saying some random sh1t cause i don’t remember the question well</p>
<p>Question: what was that geometry problem with the overlapping triangles and it said to solve a+b+c+d+e+f or something like that. I never even seen this crazt problem ever… -_-</p>
<p>wait… was 60 the complete side or just half the side? cause if it was the WHOLE side that might be my error</p>
<p>@howmanyofme</p>
<p>120 degree angle, and 2 90 degrees = 300 degrees. </p>
<p>n-2 * 180 = degrees in a shape</p>
<p>360 degrees in that , minus 300 degrees = 60 degrees</p>
<p>so all together you have a 30/60/90</p>
<p>use the side of 12 with trig and that 30 degree angle to find the length of that small triangles side. Then, use that side u just found, add it to the other side that was given(i think it was 20), then use trig once more, and it will give you 30sqrt3</p>
<p>@Descuffit - was 540 it was fairly simple…</p>
<p>it was just all substitution</p>
<p>i ended up getting 540-a-b-c-d-e-f=0</p>
<p>and i believe it was right</p>
<p>@byahnoob I thought it was 360</p>
<p>@byah: Can you explain it to me?</p>
<p>@Lolol1 how come no one reads the first page lol…
and byah it was 360.</p>
<p>180 - (a+b) + 180 - (c+d) + 180 - (e+f) = 180
subtract and rearrange. you get 360.</p>
<p>what was the answer to the texas one? I, II, and III?</p>
<p>@ulovetoy - was it 360… **** maybe i forgot to subtract the other 180 -.-</p>
<p>or I’m not sure</p>
<p>@jellomonkey - i think it was I, II</p>
<p>for III, it had to be at least 6 states</p>
<p>Byahnoob, it was 1,2,3.</p>
<p>also there was a question about an intersection like (x+1)+k or something. what was the answer?</p>
<p>@swoony - yeah god damn it… i didn’t subtract the 180</p>
<p>@jellomonkey - -3</p>
<p>the question was (x+1)^2 + k???</p>
<p>@jello: I know I and II was correct for sure. I remember that the III one said that if 5 state were added with their acreage and it would be 4.9 million arces.
So I believe that it was all three (not sure).
@swoony: how do you even add varibles together???</p>
<p>I said I and II as well because the third one didn’t necessarily have to be true but the question said, why one has to be true so, only the 1st two had to be true. The 3rd one could be true or not so, only I and II made sense</p>
<p>@swoony idk lol.</p>
<p>And everyone:
Texas - I, II, and III.
30sqrt3
length of circles was 12
a+b+c+d+e+f = 360
perimeter of triangle = 240
last circle geometry with shaded region = 50pi - 96
divisors by 3 - I and III
the 5 numbers with only 3 known numbers asking for the mean: II and III</p>
<p>did you guys think this was rather hard? -1 will get me at least 760?</p>
<p>@aashish: It better not be just I and II. Otherwise it would be the trick question of the decade.</p>