Official June 2012 SAT Math (US)

<p>I don’t remember the 5/64 or whatever that question was at all. Can anyone with a good memory retell the question? Now I’m kind of worried that somehow I skipped that question. All I know is that it had something to do with cards, which I don’t remember.</p>

<p>@highedumacated</p>

<p>lets put in 6 for p, and 3 for r (must be positive integers)</p>

<p>l6-(-3)l = 9
l6l + l-3l = 9(absolute value of -3 is 3…, and that + 6 = 9)</p>

<p>@supersaiyan</p>

<p>Bob gave 3/8 of his stuff to Phil, and then gave 7/8 of the rest of his stuff to Travis, what fraction does Bob still have stuff?</p>

<p>to do this, assume bob originally had 64 stuffs, he gave 3/8 of it away, which would leave him with 40 stuff. He then gave 7/8 of the 40 stuffs away, which would leave him with 5 stuffs, which gives you the 5/64 answer</p>

<p>They gave you 120 degrees, so you had to divide by 2 to find a 30/60/90 triangle. The 60 was opposite of the 30 degrees and the base was opposite of the 60 degrees, thats why i put 60 sqrt 3</p>

<p>@Supersaian
Some dude gave 3/8 of his CDs to his friend, and then 7/8 of his remaining CDs to his other friend… it asked how many he had left.</p>

<p>@supersaian - it was a grid in question
i think</p>

<p>a guy gives 5/8 of his card collection to a person… then he gives another 7/8 to someone else</p>

<p>how much of his original collection does he have left or something of that sort</p>

<p>anyhow i got 5/64</p>

<p>I got 60 rt 3.</p>

<p>crap was it really 60sqrt3?? SHOOOOOTTTTTTT</p>

<p>damn i got 1 wrong… f</p>

<p>eh -2 so far… :l missed the rt 3 question and for the shift I put g(x)= 0 , b/c I thought it shifted to the right by 4.</p>

<p>@howmanyofme - for the g(x) one … do u know what the question was?</p>

<p>I thought it said f(x-4) , what’s the graph, so I put g(x) is 0 . . . but apparently it’s -4.</p>

<p>Okay well, time to cancel? LOL</p>

<p>It was 30sqrt3…</p>

<p>it was a 30/60/90</p>

<p>they gave you line segment lengths
use the one that had 12 with trig to find the rest of the one with 20(cant rmember what it came out to), then use trig again with the complete side you just found to find that unknown length, which came out to be aproximately 51.something = 30sqrt3</p>

<p>o nice i put -4 too -4 or -2 I’m not sure but i think i put -4</p>

<p>… that question was ez though ahha replace x with x-4</p>

<p>@Lolol1 - do you remember the answer choices??? i think i put 30sqrt3 too but I’m not sure</p>

<p>I put 16 for the circles/line segment one? I found there were 8 lines and the radius was 2</p>

<p>Also pretty sure it was 30sqrt3. Because after doing the geometry of the problem, you would be left with rationalizing 90/sqrt3. That comes out to 30sqrt3</p>

<p>@yankeedood1202 - did it ask for diameter of the whole circle all the smaller ones made or diameter of the smaller circles together??</p>

<p>cuz im gonna f myself if i read it wrong</p>

<p>i also say its 30 sq.root 3</p>

<p>it was 12 yankee, the line segment it asked for didn’t stretch out completed across all the circles, it stopped at the center of the circles at the end. the total length of the circles was 16, but you had to subtract the radius of the circle twice because they weren’t included in the line segment, which gives you 12.</p>

<p>@Lolol1 - i <3 you … k i got 12 too… i was pretty sure i read it correctly…</p>

<p>ooo i was soooo scared</p>

<p>@byah</p>

<p>it was like 90sqrt3, 60sqrt3, 30sqrt3, 30sqrt2, and something else.</p>