**Official June 2013 SAT II Math 2 Thread**

Test Preparation SAT Subject Test Preparation
81

<p>Dunghy: You are originally x ft away at a 30 degree angle, and move 30 ft closer and the angle becomes 45 degrees. Height remains constant the entire time. In terms of x and 30 degrees, the height is x/sqrt3. In terms of x-30 and 45 degrees, it is just x-30. Now we have the height in two different expressions, set them equal to each other and get 41.</p>

<p>Got the sphere one wrong, it is indeed point + circle. <a href=“https://en.wikipedia.org/wiki/Sphere–sphere_intersection[/url]”>https://en.wikipedia.org/wiki/Sphere&#8211;sphere_intersection&lt;/a&gt;&lt;/p&gt;

82

<p>@alex, i got -4… the y-intersection was at (0,4) and the area was 2, so the height of the triangle was 1. using the principles of rise over run, the slope was -4…
also, the question didn’t say that the lines intercepted at x=1 (not sure though)</p>

83

<p>@myButler, not sure what two points you used but everything you said is right. Yes, the question didn’t say the lines intercepted at x=1, but that is what you need to figure out. Since the height of the triangle is 1, the x coordinate on the line x=y must be 1, meaning the point has to be (1,1). Do slope formula for points (0,4) and (1,1) and you get -3.</p>

84

<p>is it ok to post all my answers (i copied them all) now or not because some people in the west may not have taken it?</p>

85

<p>I think that the equation can have 0 real roots because, if the constant K is equal to 0, the rational root theorem would yield 0 possible real roots</p>

86

<p>i was pretty sure that it was -3, i also graphed it… the intersection was at x=1 because the area was 2 and
area of a triangle: .
0.5<em>base</em>height
base=4 (cause of the point given)
4<em>0.5</em>height= 2
height (x-coordinate)= 1</p>

<p>am i wrong??</p>

87

<p>For the slope of line L and area of triangle, I got -3 as the slope. This is my work:
Area of triangle=. 5bh
.5(4)h= 2 because the area is 2
h= 1
Point of intersection between the two lines is (1,1) since the other line is y=x.
To find slope, (4-1)/(0-1)= -3.</p>

88

<p>@Nuggers, oh fork, I’ve completely ignored that part.</p>

89

<p>If the constant K is 0, then there’s an intersection at (0,0).</p>

90

<p>what did people get for the one with the triangle and you are given tan a = 1/2 and you need to find sin b</p>

91

<p>Was the range for the box plot thing 13??</p>

92

<p>Can anyone else confirm the inverse proportion question and increasing x value function one?</p>

<p>EDIT: Yeah, range was 13.</p>

93

<p>**** for the root question i think i got it wrong i put one but it could have all the coefficients equal zero right? all how many questions can you get wrong if you don’t skip any and still get an 800</p>

94

<p>i got 9.375 for the inverse one</p>

95

<p>If the curve is 44=800, then 5 wrong is still an 800.</p>

<p>I got 9.375 also, but I heard 37.5? Can anyone confirm this question?</p>

96

<p>i got 9.375 for the inverse proportion thing,too</p>

97

<p>@jsteinberg13 i think every one is done by now!</p>

98

<p>37.5 would be if it wasn’t squared i think. i am 99 percent sure 9.375 is right</p>

99

<p>Wasn’t it sin a = 1/2 and they asked for sin b? I put 1/4</p>

<p>I got 37.5 or something like tat for the inverse opps. </p>

<p>I put 1 real root because you always have to have an even number of complex so 5-4=1. But very unsure of this one.</p>

100

<p>I just checked my calc and I also got 9.375</p>