<p>I put the period pi/4 (dunno why), that's my only wrong answer (till now :D)</p>
<p>i put 4 pi :(</p>
<p>anybody has a math iic curve prediction?</p>
<p>"parametrics intercept = 7"</p>
<p>Uhh, I got 1/3 or -1/3. I set x = 0 to find t, and then plugged in t into the y equation. There's no way it could have come out to be a whole number. Wasn't it x = 3t + 7? And y = 2t + 5...so y = 2(-7/3) + 5 = 1/3.....</p>
<p>yeah i got -1/3 for the parametric</p>
<p>anybody remember the last problem? i thought they said the product for the consecutive six numbers are the multiple of 3, so i think A, B, C, are 1 and 2 and 3....dunno, i was in a hurry at the last problem because i am out of time, i guess i didn't read the problem carefully.........
by the way, for those of you who had taken math IIc before, is this test a hard one compare to the ones in the past? i just hope the curve would be lower.
oh by the way, for the one problem that ask for the asymptotes, isn't y=0 an asymptote too? since the X power on the top is lower than the ones at the denominator.</p>
<p>the intercept was -1/3</p>
<p>the equations were</p>
<p>x=-3t + 7
y=2t-5</p>
<p>x = 0 @ t = 7/3</p>
<p>y = -1/3</p>
<hr>
<p>joyful: if you added up the other digits, you would see that it had to be either 5 or 8 (sum of digits must be a multiple of 3).</p>
<p>someone earlier in the thread said that it was 5.</p>
<hr>
<p>curve? probably normal. the test was very manageable, we seemed to have been killed by dumb mistakes. except for 50 ... how did you do 50?</p>
<p>it was 5. the question said 4,abc,239,040 was the product of six consecutive multiples of three. what is a+b+c?
i just used guess and check cuz i had time</p>
<p>okok, i get 50 now, uh.....i misunderstood the question since i was out of time, anyways......i skiped 2 questions and i found out i missed so far........the more we discuss, the more mistakes were found</p>
<p>i missed 2* so far</p>
<p>yea, i remember doing 50 now, i got 5 and for the parametric i got 1/3...hope that's the right answer</p>
<p>did anyone use RUSHsats to prepare? the curve for those are i think 4-5 wrong still is 800. so far, i have potentially 2-3 wrong. so <em>crosses fingers</em> i should be okay.....</p>
<p>but i have a knack for doing stupid things. on the PSAT i got one wrong on the math because i wrote in the book "2" solutions but bubbled in "1" instead....because i'm stupid like that. stupid errors...they bucked me 30 points for that one problem!</p>
<p>anyone remember any more problems? and discussing is legal right? some say you can discuss everything and some say you can only discuss solutions and not problems...what are the rules exactly?</p>
<p>two weeks of waiting you guys, patience i have not.</p>
<p>"the question said 4,abc,239,040 was the product of six consecutive multiples of three. what is a+b+c?" Since the number is the product of six consecutive multiples of three, it is also a multiple of nine. (Any even multiple of three is also a multiple of nine because 3 x 3 = 9.) The sum of the digits of any multiple of nine is also a multiple of nine. Therefore, the sum of 4+a+b+c+2+3+9+0+4+0 has to be a multiple of nine. The answer is 5.</p>
<p>ooo that makes a lot of sense. thanks ellen.</p>
<p>The question was "If (k,6) is a point on the function f(x) = log(base2)(x^2+12x), what is a possible value of k?</p>
<p>Well, you just have to use the rule that states : </p>
<p>"If log(baseX)y = c, x^c = y. </p>
<p>So therefore, because 6 = y, 2^6 = x^2 + 12x.
And by solving:
64 = x^2 + 12x
0 = x^2 + 12x -64
0 = (x+16)(x-4)
x=-16
x=4</p>
<p>-16 was one of the answer choices, and is therfore the correct answer.</p>
<p>hey you guys can tell me the answer to this IIC question, from the sunday test. I am bad at these types of questions, the visualization ones:
What is the set of points in space that is 2 units away from line L? I figured in space means it is 3 dimensional. So the answer a circle and 2 other lines and one other line, are out. So there are two answers left. One is a cylinder of radius 2 (my first answer) and infinite height, and a sphere of radius 2 (I changed my answer to this). I cant really make up my mind but I think its the cylinder. If you know please answer.
Another question I didnt understand, that no prep book covered.
there are three planes, lets say J,K,L,. Their equations, respectively:
x+y+z=2
x+y+z=3
x+y+z=1.5
What can you say about em? The answers referred to their parallelism, like all are parallel, none are, J is in between K, vice versa, and what not. Their were coefficients in front of the variables but I divided them out. I guessed none were paralell but I think since they all have the same coefficients (1) then they are parallel, but L is in between the others. However, that is mere speculation. I never learned how to do this. Any help is appreciated.</p>
<p>It seems the more obscure/higher math the question, the easier it is. Judging by the test and the prep I have taken, the algebra II problems are almost always harder than the Trig problems. Number 50 on my test seemed pretty easy (Please confirm my answer).3 statements, which is possible (can be, but not must be)?
I. sin^2 +cos^2=2 no
II 2sin^2 +cos^2=2 yes
III sin^2 +2cos^2=2 yes.
Damn it, I have so much anxiety. I am so afraid that I read the question wrong because it seems too easy.
For statement II, x=90 or pi/2
For statement III x=0.</p>
<p>And another I wasnt sure about, If R and S are real, and r=6 +i(s-2) (obtained after solving for in an equation) then r is 6 right? becuase the only way for R to be real is to remove the i, by making S=2.</p>
<p>bump Can someone help me with my math problems?</p>
<p>For the first question, it sounds like the answer is definitely an infinite cylinder of radius 2. Think about it this way - at any point along the line, the set of points that are less than 2 units away from the point is a circle - combine the sets all the points on the line, and you combine all the circles, which gives a cylinder.</p>
<p>The lines are all parallel, and you were correct on the "number 50" problem.</p>
<p>thanks for answering my problems mrognlie. Damn I shouldnt have changed my answer on the Line L problem. Stupid.
One of the answers to one of the problems just popped into my head like 6 hours after the test. It wasnt an answer but just the way to get it. I forgot, that to get the inverse of a graph, given the graph, you just switch the X and Y points around.
2 wrong, 1 guess and the rest I dont know about.</p>