<p>3/5 (10char)</p>
<p>SCORE. Okay, good. I thought I did something stupid. =D</p>
<p>I took the test today and spent way too much time on some dumb problems plugging in numbers that didn't work by coincidence. I ended up skipping/not getting to 13 total. It looks like most of the ones i answered are correct, though. Everyone keeps arguing about the set of points problem, but it is definitely two circles, because they want the whole set and four points is only a fraction of that set. I had a similar problem in Barrons practice book. There was a question that i may have done wrong about the rectangle and its base diagonal. Something like: A rectangle has a height of 3 and a base diagonal of sqrt(85), what is the longest diagonal in this rectangle. I assumed a "base diagonal" is a diagonal line across the base of a 3d rectangle, so the longest diagonal would the the hypotenuse of the triangle formed by the height and the base diagonal length, correct? (dont remember the # i got, but i think thats how i solved it). For the triangles on i got 3/5, but thats only if similar triangles have equal angles.</p>
<p>OK, I left I think 3 blank... heart rate, sequence/series, and the funky triangle.</p>
<p>I feel really confident about the other 47, so hope for an 800!</p>
<p>Also, what if the big-bad college board comes through and cancels all of our tests for our discussion here.</p>
<p>And it's four points... I don't remember exactly how the problem was worded, just that I had a moment of epiphany.</p>
<p>i change my answer
it was def 3/5
but was there a choice for 4/5?</p>
<p>o snap so far i omitted 7 and haven't missed any...i wonder how many i actually missed in relaity</p>
<p>Thank god. I was freaking out about the 3/5 because a lot of ppl said 4/5... GAH. Okay, I think I didn't fail this time. 750+ hopefully... so I don't end up with the SAME thing as last time. Grrr...</p>
<p>
[quote]
I took the test today and spent way too much time on some dumb problems plugging in numbers that didn't work by coincidence. I ended up skipping/not getting to 13 total. It looks like most of the ones i answered are correct, though. Everyone keeps arguing about the set of points problem, but it is definitely two circles, because they want the whole set and four points is only a fraction of that set. I had a similar problem in Barrons practice book. There was a question that i may have done wrong about the rectangle and its base diagonal. Something like: A rectangle has a height of 3 and a base diagonal of sqrt(85), what is the longest diagonal in this rectangle. I assumed a "base diagonal" is a diagonal line across the base of a 3d rectangle, so the longest diagonal would the the hypotenuse of the triangle formed by the height and the base diagonal length, correct? (dont remember the # i got, but i think thats how i solved it). For the triangles on i got 3/5, but thats only if similar triangles have equal angles.
[/quote]
</p>
<p>I found the answer by saying that the longest diagonal = sqrt(length^2+width^2+height^2) </p>
<p>sqrt(85)=length^2+width^2, so I went from there...</p>
<p>Yes it was two circles, because all points distant from a line should be a cylinder, and if you add in the plane it makes them circles.</p>
<p>To solve the heart one, graph the sin function, and measure the distance between the tops of the waves. This is the period of the function in minutes. Divide by sixty to get the period in hours. Divide 2.5 by that number to get the answer. (it was 1 btw).</p>
<p>The answer was 1? or was it 60 or 120?</p>
<p>Guys, when you are talking about raw scores, like 44/50 is lowest you can get for 800.. do subtract (1/4)*(# you got wrong) from how many you got right to get that number?</p>
<p>yes, u have to do 1/4*# wrong to get the "raw score." </p>
<p>about the perpendicular to plane thingy:
it said what set of points are four inches away from line AND five inches away from plane. that is a 2-dimensional area. set of points four inches away from the line make two parallel lines that are eight inches apart. set of points five inches away from plane make two lines, 10 inches apart, that are perpendicular to the other tow lines that are parallel to the line. since the questions says AND, you have to find where these two sets intersect, which is four points. </p>
<p>hearbeat question:
it was randomcrap*sin(2 pi t) + random crap, where a period of the function represented the lenth of one heartbeat. the period of a sinusoidal function is 2 pi / b (y=asin(bx)+c). b in this case was 2 pi. 2 pi / 2 pi = 1. therefore, one heart beat is one second. it will beat 60 times in one minute (which is 60 secs). tell me what u guys think of this. i know i did the heart one correctly but im not so sure on the plane question. and i omitted the last question cuz i was retarded...</p>
<p>Here's an explanation of the heartbeat problem:</p>
<p>Why plugging in wasn't the solution:</p>
<p>The equation included sin (2PIxt). The 120 or whatever constant value doesn't matter, so those of you that plugged in to get an answer of 120 were mistaken (no insult to your intelligence because it seems to have been a fairly common mistake). The reason why the 120 doesn't matter is because that only represents the vertical shift of the graph.</p>
<p>Now, here's how you get to the correct answer (60):</p>
<p>the period of a sine function = 2PI / B (the value multiplied by the variable, in this case, 2PI). Hence, the period comes out to be 1, which is the number of heartbeats per second. That's 60 heartbeats in a minute.</p>
<p>OK guys what do you think the curve is going to be? 45 or 43? or 44 maybe? or maybe 46? How about 44.5? jk but for real this was ballin' easy so I'm thinking 45?</p>
<p>It's pointless to speculate about the curve. There's no way to accurately judge the performance of all of the test takers by simply asking such a limited pool.</p>
<p>By the way, how'd the test go for you guys? I didn't take the test myself, but I was able to solve the heartbeat problem by looking/asking around for the actual question. From the looks of it, the test doesn't seem to have been all that difficult if that was one of the hardest questions...haha. Good luck, all. Don't sweat a couple of questions. Let me know if I can help out with any other problems. Just let me know the question or the specific details.</p>
<p>well aren't you the cocky one, sprtsman14. lol</p>
<p>can anyone think of other problems ?</p>
<p>okay, solve this one then:</p>
<p>
[quote]
about the perpendicular to plane thingy:
it said what set of points are four inches away from line AND five inches away from plane. that is a 2-dimensional area. set of points four inches away from the line make two parallel lines that are eight inches apart. set of points five inches away from plane make two lines, 10 inches apart, that are perpendicular to the other tow lines that are parallel to the line. since the questions says AND, you have to find where these two sets intersect, which is four points.
[/quote]
</p>
<p>I still think it's a circle. It needs to be inclusive of ALL the points in the set. 4 points is not all. I'm not sure if the problem said some of the stuff stated above... someone else verify?</p>
<p>the only things stated in the question were: line is perpendicular to plane, set of points are 4 inches from line and 5 inches from plane.
i told myself not to get involved in this argument, but when do I ever listen to myself?? so here's my opinion: it's definitely 2 circles. the 2 circles are parallel to the plane: one is 5 inches above and the other is 5 inches below. then you stick the line through the centers of the circles so that it cuts through the plane and both circles. if the circles have a radius of 4, then the points on each of the circles are 4 units from the line.</p>