<p>For the 2006 exam, you needed the following to get a 1, 2, 3, 4, or 5…
5: 106-180 points
4:85-105 points
3:68-84 points
2:47-67 points
1: 0-46 points (I think I MIGHT be able to get this…)</p>
<p>However, I saw somewhere that the curve is a bit harder now, so I’d aim for 80 points to ensure a 3. </p>
<p>This is how you do it:</p>
<p>Take your multiple choice score, subtract the # of answers you got wrong over 4, and multiply that by 1.125.</p>
<p>Take your 2 FRQ scores, and multiply them by 2.75</p>
<p>Multiply your DBQ score by 4.5</p>
<p>Add them all together to get your final score.</p>
<p>So, for example, if you got 50 right on the multiple choice and got 30 wrong, you would subtract 30 divided by 4 from 50, which would be 50-30/4=42.5 (I think they round it up to 43, not sure)</p>
<p>Then if you got two 5s on the FRQs, and a 5 on the DBQ, you follow the method:
(5<em>2.75) +(5</em>2.75)+(5*4.5)=50 </p>
<p>Then you add the 50 with 42.5 and get 92.5 which rounds up to 93…so with 50 multilpe choice right and three 5s you’ll get definitely a 3 and probably a 4. </p>
<p>At least, this is what I think, if I"m wrong someone please let me know…</p>