<p>@dwang21 it has polar bonding but non polar molecule bc its symmetrical</p>
<p>@Dwang21 the answer to the nonpolar bonding question was a diatomic gas. CCL4 has polar bonds but is a nonpolar molecule.</p>
<p>Wait! Ccl4 has polar bonds, but overall, the molecule itself IS polar, due to its tetrahedral shape.</p>
<p>@thesmiter, you are wrong. CCl4 is NOT polar. The tetrahedral shape makes it nonpolar.</p>
<p>@bannedhero</p>
<p>[What</a> is conjucate acid and base? ? - Yahoo! Answers India](<a href=“Yahoo | Mail, Weather, Search, Politics, News, Finance, Sports & Videos”>Yahoo | Mail, Weather, Search, Politics, News, Finance, Sports & Videos)</p>
<p>no… okay so imagine u have a h20 molecule. if it gains a proton (acting as a base) it becomes H3O+. </p>
<p>now that you have H30+. it acts as a <em>acid</em>(giving up a proton) thus becoming H20.</p>
<p>the only thing i don’t get about this question is that H20 and OH- would work too as well as HF and F- because HF and F- is a buffer it must be a conjugate acid base pair.</p>
<p>when i was taking the test i don’t remember OH- or F- being a choice. but that might just be me working too fast and not looking at all the choices</p>
<p>[Brønsted?Lowry</a> acid?base theory - Wikipedia, the free encyclopedia](<a href=“http://en.wikipedia.org/wiki/Brønsted–Lowry_acid–base_theory]Brønsted?Lowry”>Brønsted–Lowry acid–base theory - Wikipedia)</p>
<p>Umm I think you have the lewis and Brønsted–Lowry theory mixed-up. Acid GIVE protons according to the Lowry Theory (Modern)…
In the case of the Lewis theory, acids accept electrons</p>
<p>“it acts as a base(giving up a proton)” that is wrong. Bases according to the modern theory, bases accept protons. HCl is an acid because it donates the H+. NaOH is a base because it accepts a H+ to form water. </p>
<p>I think HF & F- pertained to another question, not for the acid-base pair. I am pretty sure the answer is H20 and 0H- because H20 can act as both an acid and a base.</p>
<p>that test was really easy. probably on the same level as PR practice tests.</p>
<p>and i’m pretty sure that conjugated base-acid pair question was h2o and oh-. i don’t remember seeing a hf and f- choice…</p>
<p>nh3 + h2o -> nh4+ + oh-
base acid CA CB</p>
<p>Does anyone remember the TFCE question where it asked whether Na was easily ionizable and why? Also, how many TT but not CE answers did people get?</p>
<p>Mistah, which ones did you take. I thought similarly, it was nice that they mentioned allotropes.</p>
<p>I got a TT without a CE. I think in the case of sodium, the question did not ask if it was easily IONIZED, but that if it was easily OXIDIZED.</p>
<p>UHHH DID THE QUESTION ASK FOR CONJUGATE BASE- ACID. VERSUS CONJUGATE ACID- BASE? if it was the latter the answer is H3O+ / H20… </p>
<p>damnnnn that was such an easy question then</p>
<p>Sodium is definitely easy oxidized, though. I don’t remember what the second statement was.</p>
<p>It asked for Acid- Conjugate base</p>
<p>H20 & 0H-. Can we seriously stop arguing about this question? HF & F- was not even one of the answer choices.</p>
<p>The partial pressure of N2 was 100 or 200? 2n N2 to 1 n O2</p>
<p>oops sorry yeah it was whether it was oxidized easily. The second part was something along the lines of “sodium is eager to lose electrons or something”</p>
<p>D you guys remember the questions with matching? Especially the group with “this is not affected by tempreature” and the choices were like mass, molecular mass, density, boiling point, freezing point? I remember using density, molecular mass and something… Des anyone remember? >.<</p>
<p>Also for the sodium one, the first one was true (oxidized) but I distinctly remember the second part being false</p>
<p>Wait…I finished on #70…does that mean I skipped a question by accident and forgot? If so, I’m going to have to cancel this score. Darn, and I thought I did so well…</p>
<p>But sodium does lose electrons easily. Maybe the second statement actually said something like “gains electrons easily”? I also remember as having this as TF.</p>
<p>Moles of liquid was mass
Temperature was density, if it asked for change</p>