<p>@Baneling - no its 6!</p>
<p>there were 8 cars and 1had to be in front and the other in back so 6 cars to arrange…</p>
<p>6!</p>
<p>correct me if I’m wrong but I’m pretty sure it said some color had to be in front and the other in back? I’m not sure what the question is</p>
<p>Yeah, I thought it said a specific one was in front and the other was in back. I really hope so.</p>
<p>@StudiousMaximus - im not sure if there was 2 of the same color that was specifically in front or back then the answer isn’t 6! if it was just 1 then 100% its 6!</p>
<p>Definitely one in the front and one in the back. 6!.</p>
<p>Though to be honest, I suck at this and you shouldn’t trust me on anything I say that’s remotely math-related.</p>
<p>Yeah, it’s 6!</p>
<p>There were 8 different colored cars, and they already said that one specific color had to be in the front, and another specific color had to be in the back (I think it was like red in the front and green in the back?) Regardless, that leaves 6 distinct cars in 6 distinct positions (in the middle 6)… You use permutations, and yup. It’s 6!</p>
<p>good **** guys… i think 6! was already mentioned in the earlier pages of this thread</p>
<p>Omitted 0, missed 0, so far.</p>
<p>Yay!</p>
<p>Wait sorry sorry if I’m totally behind on the info so far, but for the p^3 question, one roman numeral was that the prime factor had to be positive for something, so that’s right. and another roman numeral said that there were 3 distinct FACTORS. </p>
<p>Did it say prime factors? Because if it did, then yeah, you’re definitely right, there would only be one distinct prime factor p. HOWEVER, if it was just “3 distinct factors”, then wouldn’t that also be right?</p>
<p>p, p^2, and p^3 are all distinct factors are they not?</p>
<p>@AlphaR: Nice!</p>
<p>^ Didn’t it say distinct prime factors? Or something like that? Technically, 1 and p^3 are factors. So 1, p, p^2, and p^3 are factors, which makes 4.</p>
<p>yeah i picked 6! too but since the cars could be going in both direction (left or right) red can be leading the cars or in the front in two ways…</p>
<p>last question anyone?</p>
<p>Crap, well then, I suppose we can’t know unless we see the question. Thanks nonetheless…</p>
<p>Also, I don’t think we had to take direction into consideration… I mean you’re right, but was there an answer choice of 2*6! ?</p>
<p>^I think there was.</p>
<p>But it said how many ways can they be ordered. I don’t think it matters which direction they’re facing. I wish I could read that question again.</p>
<p>Any more thoughts on the p^3 question?</p>
<p>I omitted that :/</p>
<p>are you guys sure it said 3 prime factors for the p^3 question? i think it remember it saying 3 distinct factors.</p>
<p>and is there a consolidated list of answers?</p>
<p>I got it wrong. Pretty sure I did anyways. </p>
<p>What was that awful question about how many incongruent triangles can be formed? Side of 4 and 6, and an angle of 42 degrees. I skipped it.</p>
<p>Right I thought it said 3 distinct factors, like it wasn’t a limitation. I just thought it meant this positive number has 3 factors, could be more, but no less?</p>
<p>I don’t know… then again, we have to see the problem.</p>
<p>^^ It was no triangle.</p>
<p>Was it impossible to have such a triangle?</p>