<p>16/6 is fine. it reduces to 8/3. if the fraction fits, it’s acceptable as long as it reduces to 8/3.</p>
<p>Three triangles have a total angle of 3*180 =540
subtract 3 right angles (270) and subtract 140 (the given sum of the other angles), and the remaining angles r,s,t add up to 130</p>
<p>Someone compile the answers please ?</p>
<p>What was the answer/numbers for the parallelogram one?</p>
<p>I only remember that one triangle that was AB=BC and something parallel to something.
From the 30 degrees they gave you, the sum of the opposite 2 were 60</p>
<p>guys was the apple problem experimental?? it had like c and n in it, i think i made a stupid mistake on that one</p>
<p>the deer problem anyone? Please!!! I forgot what the question was and the answer choice I put . ! (:</p>
<p>Can someone please explain the last question on the last math section. </p>
<p>The question read: If g(b) is defined by the table above, what is g of the next term plus two. I could not, for the life of me, figure out what they were doing to the independent variables to produce those outputs. From what I remember g(-4)= 9, g(-3)= -7, g(1)=0, g(0)=3 or something like that…any ideas? I didn’t see anyone comment on this problem yet.</p>
<p>all i remember is that the answer was -3. (a)</p>
<p>@peter yes. Apple was experimental.</p>
<p>In reading this thread, I just realized a ridiculous mistake that I made. Coordinates for the center of a circle are (8,9) and the radius is 10. How many times does it pass through the axes? I figured it would reach the positive Y axis, and the positive X axis, but it wasn’t long enough to reach the origin (as the distance b/w the point and origin was 12, 12>10). </p>
<p>Then I answered 2 thinking I had beaten the problem…only to realize now that if it passes the X or Y axis once it has to come back over. ■■■. Assuming no other stupid errors, I’m at a -3. ■■■.</p>
<p>I also made a very dumb error. I somehow made the dog in the dog problem to be 18 inches long… I’m @ -2 now.</p>
<p>does anyone remember a question where there was a graph and it listed different groups of singers, like tempo, soprano and etc?</p>
<p>It asked if all of group A went into Group E how many more sempranos would it more than group C or something like that</p>
<p>Sum of tenors of group A and group C is how many more than the number of tenors in Group E.</p>
<p>I totally forget the question, but I believe the answer was Seven.</p>
<p>It was 7 I think arctk3 because it totaled to be 21, and the other had 14?</p>
<p>@Arc I remember the answer being 7 for some reason. It was a pretty straight forward question, I’d be surprised if I got it wrong.</p>
<p>Ok seems like everyone else got 7 as well lol</p>
<p>I believe the tenors/sopranos section was experimental.</p>
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<p>Actually, if it went pass the origin, it would only pass three times. Going pass the origin means passing both the x-axis and the y-axis at the same time. You originally have four: a) crossing y; b) crossing back over y; c) crossing over x; d) crossing back over x. </p>
<p>But, if it passed through the origin, b and c would be the same. The answer would then be three.</p>
<p>Checking the origin needed to be done.</p>
<p>It’s still 4 then. Good.</p>
<p>The tenor section was not experimental (unless you had a 2 tenor questions)</p>