<p>2 intersections
15 numbers</p>
<p>does anyone remember what #18 on the grid in was?
i dont remember the question but it involved finding the value of x for f(t) = f(2t) or something, im not really sure what the question said.</p>
<p>No, I didn't have that parabola. It had roots at something like (-2,0) and(5,0). I remembered how to do it after the test, but I guess I should have reviewed conics BEFORE the test ;)</p>
<p>omg i had trouble with that one too!</p>
<p>I got one intersection point for the first one ( dunno if thats correct)</p>
<p>dont have any reccolection of the other one</p>
<p>dieu..........please have separate threads for different tests</p>
<p>madamebovary, i think for the
"3 condition: 1<=n<=20
n<5 it is even
n<14 it is odd" problem, i got 15..</p>
<p>it was n>5... if it is even...... so, 6, 8, 10, 12 14, 16, 18, 20
n<14 if it is odd... 1, 3, 5, 7, 9, 11, 13</p>
<p>8+7 = 15, did anyone else get this?</p>
<p>whats dieu?</p>
<p>wasn't it like this
n>5 is even
n<14 is odd
or am i mistaken</p>
<p>edit: yeah i got 15</p>
<p>dancingbear, are you talking about the very last grid-in? It had a polynomial and was like for which value of x is f(2x) = 2f(x)? I had no idea on that one :( Hoping it was experimental ;)</p>
<p>abdulk, how would the circle only have one intersection point? that would only happen if they were tangent, and i dont think they were.. i put 2 as well.</p>
<p>zpmqxonw, yes, that was the question. i think that was my only grid-in, so i dont think it was experimental.</p>
<p>can someone explain to me why its 12</p>
<p>not that's not experimental, i've seen that in the blue book</p>
<p>you solve it by setting them equal to each other
for example:
say the equation is f(x) =2x+3
set f(2x) = 2f(x)
2(2x) + 3 = 2(2x+3)
then solve</p>
<p>Yeah, that ones definitely two. And I got 15 for the other one too I think. I just wrote out all numbers 1-20 and then crossed off the ones that didn't meet the criteria.</p>
<p>zpmqxonw...i dont think thats experimental because i have a similar question...</p>
<p>nadame.. i didn;t mean 12.. just a typo that i changed.. sorry</p>
<p>why only two intersection points then?</p>
<p>I just remebered the problem they had with the 3 inscribed circles,and saw that each small circle intersected the bigger one at one point</p>
<p>anyone got a question about the year of inauguration of a club chairman or something?</p>
<p>abdulk there was no picture for the problem. you are talking about a different one. just merely draw the two circles for the answer...</p>