<p>^agree with both</p>
<p>For the first question, i got 7, but I’m not sure exactly what the function was.</p>
<p>It was six for distance between the point and the origin. There was a question in one of the MAth 2 practice tests almost exactly like that. </p>
<p>The SD problem I got the same as you…hopefully, it’s right.</p>
<p>Yep, 6 for the distance (yeah it was basically the exact same as the one from one of the practice tests). And yeah, that’s right for the standard deviation (look up the formula for standard deviation for further confirmation). And nice, 7 is what i put.</p>
<p>How about the one with the line and the 5 points on the line where it asks how many distinct lines can be made? Was the answer 10? 4+3+2+1…?</p>
<p>yes the answer was 10 to that one</p>
<p>Yeah, it was 10. Any other toughies? How about the one that asked for the painted cieling and walls? I got like 789 or something</p>
<p>What about the trapezoid one, that messed me up, I tried using calculus and got a different answer. All i remember is choosing C for the answer.</p>
<p>I think that was 728 or the number around that. Just the area of the four walls and the ceiling (not the floor).</p>
<p>The trapezoid…base 1 was 2.5 and base 2 was 4. Can’t remember what the height was…but let me try to remember the problem and recalculate it. Ah, the height was 2.4375</p>
<p>Thus, the area should be… (2.5+4)/2 * 2.4375 = 7.92. Does that ring a bell?</p>
<p>Yeah, I got something less than 1000 but more than 500. For the trapezoid one I got 7.92</p>
<p>Ch33psh33p, thank you for agreeing with me on the inverse of f(x) question, its the origin haha (i hope)</p>
<p>Honestly, there’s no reason for it to be the origin. By that logic, the answer should also be y=-x (y=x is symmetric about the origin, y=-x, and y=x). While none of the answers seem full-proof at this moment, y=x seems to be the least flawed.</p>
<p>I think around the origin symmetry would be something like 1/x or x^3, if you look it up on google, but if you plug in any function and its inverse on the calc you get y=x symmetry</p>
<p>have we come up with a difinitive answer for the polynomial question with the root (2+3i)?</p>
<p>I put 2-3i just because it’s the opposite, but does anyone know the answer for sure?</p>
<p>Here’s the explanation for the last problem:</p>
<p>Using modular arithmetic, the sum of all the digits of the number should equal 0 mod 3 [For those who are unfamiliar with mod arithmetic, it basically says the sum of all the digits must be divisible by 3]. </p>
<p>So you basically get the sum as [ sum of first 7 digits ] + A + B + C = 0 mod 3</p>
<p>I think someone posted the number earlier in the thread but I don’t want to get into trouble, but if the number they posted is correct, then A + B + C is equal to 5 or 14, and 5 is the answer choice there. </p>
<p>This was my first subject test and I had been finishing pretty fast on my practice tests so I did it kind of slowly on test day and was pressed for time =[ I ended up omitting 5 and I know I made a careless mistake on one question, so I’m at 44. Just praying I didn’t make any other mistakes so I can get the 800. </p>
<p>This test was by far harder than all the other tests I’ve taken, but what’s the most frustrating was that if I had 5 more minutes I would have gotten all 5 that I omitted correct =</p>
<p>Well, my rational is that using the polynomial formula will give you two solutions b +/- determinant. If the determinant is -, then it will be replaced with ai. So you get two solutions b +/- ai or 2+3i and 2-3i</p>
<p>“The complex conjugate root theorem states that if P is a polynomial in one variable with real coefficients, and a + bi is a root of P with a and b real numbers, then its complex conjugate a − bi is also a root of P.”</p>
<p>Complex roots always occur in pairs.</p>
<p>f(x) = g(x)</p>
<p>That one with three choices, how to solve it. What was the answer?</p>
<p>Also, it’s definitely 2-3i. Thats one of those rules for imaginary roots.</p>
<p>You can either subtract them f(x) - g(x)
Or you can find where they intersect.
I think it was like I and III</p>
<p>Yeah, that’s what I got</p>
<p>I think it was I and III. Not sure what letter. I was right and II was wrong because if you think about it, when you check for the intersection point, you always look at the x coordinate, not the y coordinate. And III should have been correct because f(x) - g(x) and then checking for zeroes is essentially how you solve quadratic equations.</p>
<p>what were the answer choices to the trapezoid problem? i remember i got 8.125 but since that wasnt really one of the answers i chose the one that was closest. i hope i still got it right.</p>