<p>@battlebrick:
I got b for the absolute value question. It simplified to b(-1+a)/(a-1)=b. On my first step, I subbed a for abs(a) and -b for abs(b).</p>
<p>For the absolute value a and b one, I got -b, because I factored out the |b| to get |b|(1-a)/(a-1), and so you’re left with -|b| or -b. How did you guys get b for that one?</p>
<p>EDIT: never mind… was it really -|b| +|ab|?</p>
<p>@ haters
Yeah I got 155.13</p>
<p>@magenta I got that answer I think it was either B or D… I suck at remembering the actual letters</p>
<p>Oh, and random thing, for the slopes of the line one, I actually did law of cosines. Yay trig! =P</p>
<p>@deejayyx3
I used law of sines (AAS) for the one with side 10.2 and angles 30 and 50 and got 15.63.</p>
<p>@cherry I just did a quick guess and check with two different sets of values and got b.</p>
<p>@ cherry
i got b as well</p>
<p>@melzid: i did law of sines too!! i was so scared that i matched up the wrong angle with the wrong side,so i did it like 2 times and got the same ans</p>
<p>@FASTNEUTRINO
can u explain how to use law of cosines on the one that gives 9.something as the angle between the two lines?</p>
<p>@battlebrick
yeah i got 155</p>
<p>Does anyone remember the question 49?</p>
<p>@cherryblossom
actual problem was abs(b)-abs(ab) on top and a-1 on the bottom, iirc</p>
<p>@Melzid I don’t really think law of cosines was necessary for that one… I just did inverse tan with the slopes and subtracted.</p>
<p>does anyone remember what the -1/pi question was?</p>
<p>@Melzid: I forget exactly, I just know that I knew all three sides of a triangle made by the lines and the y-distance between the lines and solved for theta from there. XD</p>
<p>@tryingtoohard:
see post#132 where I wrote the whole problem and step-by-step solution</p>
<p>what was the y -int of the parametric eq?
it’s either -0.5 or -1/3</p>
<p>@Melzid
Thanks. Did you get b just by plugging in?</p>
<p>-1/3 for the parametric equation</p>