USA June 2011 SAT: MATHEMATICS Discussion Thread

<p>what was the answer to the question about the cube labeled 0~5?</p>

<p>Can we please stop debating over the triangle. ITS ONE QUESTION…focus on a list…I made 2 stupid mistakes, the pen one and I accidentally calculated the slope of that graph one as 9/6, not 6/9…im not whining</p>

<p>just move on, its one question</p>

<p>i put 0 for the cube one.
the one that’s opposite side 1, right?</p>

<p>@choyphin- 40</p>

<p>@alauren: Finding a non-equilateral triangle does mean the answer is incorrect (because it was stated as “must be equilateral”). However, his example is impossible.</p>

<p>@sidthekid i did the exact same thing and realized with 1 min to spare luckily
at least it wasn’t an mc so no point deduction</p>

<p>Just stopping in again cause I hate seeing people quarrel over the pen/pencil problem when the solution is so easy.</p>

<p>Each kid has 3 utensils. The average is 1.4 pencils. Therefore the average is 1.6 pens so it comes out to 3 in total. Have a good day :)</p>

<p>i think 5 was facing 1</p>

<p>what was the answer to the overlapping circles question asking you to find RS?</p>

<p>I really hope there’s a -1 curve…</p>

<p>I put 5 opposite the cube one.</p>

<p>@goodscores
lol I didn’t figure that out until I solved it a more complicated way.</p>

<p>Here are the answers according to GoodScores, the smartest guy posting here right now:</p>

<ol>
<li><p>The coordinates was like (3,-6) I believe; it had to have a negative x, but it wasn’t the one with 0 as the x coordinate. (for the y=|f(x)| one)</p></li>
<li><p>25 doesn’t work, since 75 is a multiple of 3, so it would only leave 64 numbers of 1-100 left.</p></li>
<li><ol>
<li>The lines are parallel, so the answer had to be 180-angle, which was 75.</li>
</ol></li>
<li><p>10%.</p></li>
<li><p>It was 70 and 165, yes. Use the minimum values and plug them in, and then the maximum values.</p></li>
<li><p>It was only II, the triangle was equilateral.</p></li>
</ol>

<p>5 on cube one. how about the arc of the circle with 10pi circumference</p>

<p>can someone explain the question where they got the answer to be 15 degrees? cant remember the question</p>

<p>and possible -1=800 ?</p>

<p>5 for the cube if I remember correctly.</p>

<p>It was an easy question. No thinking involved, just eliminate all of the numbers that were on sides touching 1 in the pictures…</p>

<p>the coordinates can’t be negative for the y value because it is absolute value</p>

<p>arc is 1/4 the circumference so it’s… 10pi/4 or 5pi/2 (the answer)</p>

<p>rdpgn105, it was asking which coordinate cannot be there for the absolute value…thanks for confirming my answer lol.</p>

<p>40 on the cube question</p>

<p>@rdpgn105</p>

<p>2.5pi. It was one fourth of 10pi</p>