USA June 2011 SAT: MATHEMATICS Discussion Thread

<p>I think it’ll be 105 as well. I’m just desperately clinging to my -1 (getting this wrong pushes me to a -2).</p>

<p>for the question on the highest max value, was A: (-x)^2 + 2 or -(x^2) +2… They give totally different values.
plug in 4, for first u get 18, second u get -14</p>

<p>What would be the curve for -1 in math?</p>

<p>Was anyone else really annoyed that one of the questions said like AB = BC = AC when clearly in the picture AB and BC looked significantly larger than AC? -_- why can’t they draw figures to scale</p>

<p>@blackpain- exactly</p>

<p>Curve for -1, anyone? would it be 780 or 770?</p>

<p>I wish we could appeal problems.</p>

<p>The problem was asking for the MAXIMUM value of the function. All of the functions were down facing parabolas. THE MAXIMUM POINT IS THE Y-VALUE OF THE VERTEX of a DOWN PARABOLA.</p>

<p>-x^2 + 2 is the same as -(x-0)^2 +2
vertex: (0, 2)</p>

<p>-(x+2)^2 + (-2)^2
vertex: (-2, 4)</p>

<p>4>2</p>

<p>^Black Paint I agree with you</p>

<p>but for some reason everyone keeps saying its A or B and some people give that answer…but I got that answer too and got C</p>

<p>Can someone answer me please? What would the scaled score be for -1 in math?</p>

<p>there was a q with two circles intersecting and a triangle in between them. u had to find the length of the intersection of the triangles. what was that one?</p>

<p>^2 I think it might’ve been C as well. Don’t count on everyone to remember the exact sequence of answers for the MC. That was the answer.</p>

<p>-(x-2)^2 + (-2)^2 and -(x+2)^2 + (-2)^2 both have maximums of 4. so…</p>

<p>Can anyone predict scores?
-2 Math
-5 Reading
-0 Writing with 11 essay
Is there a chance for a 2300+?
Thanks everybody!!!</p>

<p>@akshizzle101</p>

<p>I think that one was 4?</p>

<p>LOL @ “they didn’t specify which set was parallel.” The sides that were parallel were the ones that obviously weren’t going to run into each other… the answer had to have been 105. Its a trapezoid. It doesn’t matter if it was isosceles or not, whoever said that. the fourth side does not matter at all. Dissect the trapezoid and you have a set of parallel lines with a transversal. It HAS to be 105. Basic geometry guys.</p>

<p>Also, THANK YOU, blackpaint.
Basic formula for parabola: a(b(x-h))^2 + k
Where a is the</p>

<p>Not being an isosceles does not preclude x being equal to 105. One may extend the (ostensibly) parallel lines to find a transversal incising these two lines. As I believe someone said earlier, 75 and x must be supplementary. I’m not sure what the relationship between these two angles is, though, adjacent interior?</p>

<p>@dj04x7</p>

<p>Put it in your calculator. One graph is very obviously above the other one.</p>

<p>I’m fairly positive those weren’t both answers. And even if that were true, A is not the answer</p>

<p>Syndekit.
770 + 750 + 800
2320.</p>