<ol>
<li>In square ABCD, vertex A is at (-1,-1) and vertex C is at (4,2). What is the area of square ABCD?</li>
</ol>
<p>A) 9
B) 15
C) 17
D) 25
E) 34</p>
<p>A and C will be opposite vertexes, so the distance between the two points is the diameter of the square. The diameter is 5.83, and dividing it by SCRT(2) will get you the side length (45/45/90 triangles), which is 4.123. Square that and your answer is C) 17.</p>
<p>ABCD isn’t even a square…</p>
<p>^Umm, the question clearly states:</p>
<p>
</p>
<p>I’m pretty sure that ABCD is a square.</p>
<p>The question says that ABCD is a square, if you draw it out it may help you more.</p>
<p>Are you sure you have the right coordinates for point A?</p>
<p>^Yes, the math works out.</p>
<p>Assdfsd B</p>
<p>Dssdfsd C</p>
<p>I solved the problem the same way you did. I got the distance of AC as sqrt(29) and when I divided by sqrt(2), I got 3.807. When you square that, you should get 14.5. So the answer should be B. 15.</p>
<p>^ I am getting (B) as well. I don’t think the co-ordinates given are correct.</p>
<p>The coordinates are correct.</p>
<p>Are you kidding me…ABCD is not a square. The question is stated wrong. If you plot the points, the only shape that the vertices can form is a rectangle.</p>
<p>You’re correct. The co-ordinates form a rectangle with length of 5 and a width of 3. The answer is (B).</p>
<p>Yeah, I think it is a rectangle. I’d assumed that it was a square based on the wording of the question. Sorry.</p>
<p>What you people fail to realize is that a square’s depiction does not necessitate its drawing of sides parallel to the x or y axis. A square can easily drawn sideways as it is parallel to the x or y axis. Furthermore, the problem meticulously states that ABCD is a square. If one has read The Theory and Reason of CoBo Supremacy, one would know that the word of College Board is supreme and should not be inquired; thus, square ABCD is a square unless evidence suggests otherwise. If a square were not a square, then a rectangle would not be a rectangle; logic then follows that the entire theory itself would be deemed inaccurate, bringing the elaboration to a paraduxtic end. The Bong Boy’s explication of the problem is entirely correct, and we extol his generosity for such an elaborate solution.</p>
<p>^OK, so I’m not crazy after all. It is a square.</p>
<p>the answer is e</p>
<p>Lol I graphed it and counted the spaces up and the spaces sideways and multiplied. Using the distance formula and whatnot…well maybe I’m just simplistic. I got B.</p>
<p>Why the hell is this so hard?</p>
<p>5 to the right 3 up.</p>
<p>Hypo is sqrt(25+9)=sqrt(34)</p>
<p>Area is 34.</p>
<p>Well said GreedIsGood</p>
<p>Greed is an uneducated lout in addition to its being a malicious sin. Please realize that the square is ABCD, not ACDB. Know your alphabet.</p>
<p>What the heck? It can be a square.</p>