<p>I am resolving Barron How to prepare for the SAT I found this question which has wrong answer I want to make sure though,because sometimes maybe I could have missed something.</p>
<p>If A(-1,1) and B(3,-1) are the endpoints of one side of square ABCD, what is the area of the square?</p>
<p>This question has two errors the first error is its stating that is a square the values are wrong
The height and width should be x;</p>
<p>Since both vectors has different x and different y we can conclude this should be the height and the width;</p>
<p>Height = 4; Width = 2; This should be a rectangle.</p>
<p>Also lets say we didn't conclude this we know that 3--1 = 4; so 4^2 = 16 and that answer is wrong; The actual answer is 20.</p>
<p>Is there something am I missing or is this question itself wrong ???</p>
<p>I’m too lazy to do math right now, but chances are that there’s a typo in the book. Test prep books always have typos, I’ve yet to find one that doesn’t. :)</p>
<p>The 2 points given are one side of the square, so you cant compare the length and width. All that means is that the square is not level on the x/y coordinate plane. All you have to do is find the length of that side using the distance formula (d=sqr((y2-y1)^2+(x2-x1)^2), and then square that length because the area of a square is the length of one side squared.</p>
<p>What I don’t understand is that the question gives us the vectors of the two points,since distance formula is just derived from pythogrean theorem we can get the difference between points which is weird to me coz the width is 4 and height 2 even though its a square.</p>
<p>They give you the coordinate of the 2 points, and those points are connected to form a segment, the point is that the square is diagonal, not flat. Your picture is incorrect</p>