<p>In square ABCD, vertex A is at (-1,-1) and vertex C is at (4,2). What is the area of square ABCD?</p>
<p>i really do not understand how to reach an answer because when i drew a diagram i made a rectangle.</p>
<p>Who says it’s got to be a perfectly horizontal/vertical square? It’s tilted a bit. Since they gave you A and C, AC is a diagonal. You can draw the square using that if you want. (the other sides are perpendicular to AC)</p>
<p>You can find how long AC is, so you know how long the diagonal is. Since half a square is a 45-45-90 triangle, you can find how long a side is, so you can find the area from that.</p>
<p>thnx tht never registered in my brain I get it know</p>
<p>Here’s a nice formula you could use:
the area of a square A=(1/2)d^2, where d is the diagonal of the square.</p>
<p>^ Yep, that is because the area of a square is half the product of the diagonals. This product is , of course, the diagonal squared.</p>