DECEMBER 2008 SAT Subject Test: Math Level 2

<p>sorry hookem, but I know otrebmu, he’s a buddy of mine from another forum. lol</p>

<p>^ haha how appropriate, Consul Inveniamviam. Yeah they basically said “well, here’s the thing…I had a general, hazy idea about what was going on. Other than that…not a whole lot.” hahaha that’s why I’m a Spaniard when it comes to languages :)</p>

<p>^lolol, yep. That’s how I felt about it - I skipped Latin II, which is when we learn grammar and have taken 2 AP Latin classes right after Latin 1 now, lololol. My grammar is lacking.</p>

<p>Same with them!! They said their grammar was really poor, even though they’re currently translating the Aeneid in AP Virgil…</p>

<p>^lololol Yep, I did Vergil last year, but you don’t really need grammar for the Aeneid because Vergil cut off all the word endings and made ~everything look like an infinitive… haha. There lies my problem…</p>

<p>why isn’t #49 (prob question) 4/9? since you don’t know what’s the order of the two, don’t you multiply 2/9 * 2?</p>

<p>i thought that 2/9 was too obvious of an answer for the second to last problem of the test…</p>

<p>I think it was 5/9…but I agree.</p>

<p>Hey- what was the area of the box (question 3)- 96, 144?
ALso what is the area under the 2sin2x curve (someone said it was 2pi, any verification?). Answer for parametric (choice E)?
Answer for how many real roots? (Was it a quadratic or what?).
Um the one with the zeroes, was it btwn -2 and -1?
THe m and n one, four, 5? I worked it out and got 4…</p>

<p>Lol, I didn’t think they got any harder as it went along… I put 4/9 I think, but now I’ve changed my mind, kind of.
It was 2/3 local, 1/3 long dist. So, 2/3 local first call needs a 1/3 for the second so 2/3<em>1/3=2/9. I, for some reason, decided to be like “oh duh well that’s not the only way it could happen” and added that to 1/3</em>2/3 [which is really the same thing since it doesn’t specify order…argh] to get 4/9. But it doesn’t matter which call is first, so it’s just 2/9 I think.</p>

<p>bah, for some reason on the 2sin(2x) curve, I got that the height was pi/4, width is pi/2 and so 1/2<em>pi/4</em>pi/2 is NOT an answer choice… lol… I was going to go back and figure out how I screwed up, but didn’t have time. bah.</p>

<p>8 x 6 x 2 = 96. Done.</p>

<p>It’s just pi. Period is determined by 2pi/b. B was 2, so the period was pi. Base = 1/2 of the period, so pi/2. Height was 1, I think, so pi/2 x 1 = pi /2</p>

<p>Quadratic. 2 roots.</p>

<p>Yes, btw -2 and -1. </p>

<p>Ye, there were 4 sets, specifically: (+/- 1, 2) and (+/- 2, 4)</p>

<p>Oh yeah, it was 2/9. Good call.</p>

<p>if it doesnt matter which call is first, order doesn’t matter. doesn’t that mean more choices, so why is it restricted to just 2/9.</p>

<p>^Actually, 5 sets - the one’s hookem listed AND (0,0) I think.</p>

<p>Wait, Hookem, you said “Yes, there were 4 sets, specifically: (+/- 1, 2) and (+/- 2, 4)”
I am confused by your quote, do you m ean those were the exponents that worked out for both values? So the ansewr was 4 sets of m and n (exponents) = would produce equal values.
Also you said it was “just pi” , however then you said pi/2. WHich one was the answer? - thanks.</p>

<p>wait what was the period ****KKKKKKK</p>

<p>Well, the entire base was just pi, but since area is basexheight/2, and height=1, it works out to be pi/2.</p>

<p>DAMMIT inveniamviam! stupid effing mistake. UNLESS did it say that the two numbers per set had to be distinct??? That would be the magic term, because 0,0 wouldn’t work…</p>

<p>What was the answer for the log(2)x= -1.7? I really suck at logs.</p>

<p>The period is 2pi/2, or pi… so the base is pi/2, because it’s already half of the period. the amplitude is two, so the height is two. .5 * 2 * pi/2 = pi/2</p>

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<p>if order is specified, probaability is less. So it’s 4/9 for sure ;)</p>

<p>it’s 1/(2^1.7), about 1/4, or .25, so the answer is .30</p>