<p>was 1/2 a choice for the period…i might have effed that up.</p>
<p>…IS IT 2/9 OR 4/9…
for events A,B: prob (AB) = prob(BA), and since we don’t know the order of two events, don’t we have to ADD both probabilities?</p>
<p>Repost of mine and Inveniamviam’s question about the m and n exponents. 4 or 5 ordered pairs? Those were the only two viable options, and the answer depends on whether or not the question specificed “distinct numbers” in each set, which would rule out 0,0.</p>
<p>Discuss.</p>
<p>I recall it asking for integer values, so I went with five ordered pairs…</p>
<p>uhm, I would have seen if there was something like distinct numbers… I think so. I hope so.</p>
<p>crap. there goes my 800.</p>
<p>is it always min raw score of 43 to get an 800? does anyone know the highest that min has ever been…it better not be like 46.</p>
<p>BigWeight:
“lol. otrebmu, u are screwed”</p>
<p>insert fufufufufufuufufu picture</p>
<p>hookem168:
“^ BigWeight, be sensible. Just because he mildly effed up a single problem doesn’t mean anything about his chances as a whole. Otrebmu, keep the faith, sir!”</p>
<p>thanks guise. i only answered 27. i should’ve gone faster and narrowed down choices (i resisted guessing… which i now realize is irrational) and overall sucked all. </p>
<p>ok, were there multiple period questions? i put 2pi</p>
<p>INVENIAMVIAM:
“…, the limit of the parabola at x=whatever was infinite if I remember correctly”</p>
<p>can you explain why for this one? it was one of the first dozen and should’ve been easy, but i’m categorically below average intelligence in terms of math2 taking (<50 percentile)</p>
<p>@quitenicefrdrice
from my research today i believe the minimum raw score to make 800 varies from 43-46</p>
<p>how did you do : 7^6=…
Find s.
man…my 800 is gone…sigh…</p>
<p>gasp! 46?? In the words of lolcats, OH NOEZ!!! WTH, please tell me that’s not going to happen here…</p>
<p>about the “approaching infinity”…since f(x) is irreconcilably undefined at that x value (you can’t factor and cancel or anything to figure out a specific number it approaches), the answer is infinity. It’s a vertical asymptote. I graphed, just to check my intuition, and it supported my hypothesis.</p>
<p>umm. like… 7<em>7=49, 49</em>7= 343… see, so you just multiply the 7 by the last digit of the number before it, then take the one’s digit of that number to find the new digit that will be in the one’s place of the next number. then you just add whatever is necessary to make it into a multiple of 10, or whatever the problem asked for</p>
<p>Ok, the 7^6 problem was just a load of excess information to confuse you. The number was 117649. It told you that s must be < 10. The function was something like 10r + s = 117649. Since r and s both had to be positive integers, 10r must also be a positive integer. S must be < 10. All right, I can’t explain this well, but when you stick those two facts together, it becomes obvious to me that s has to equal 9, so that 10r = 11740 (or r = 11764).</p>
<p>oh yea i got that one. wasted time doing it though, tried 1-8 before i got to 9
my long way first included dividing by 10 so r + s = 117649/10 = [decimal], then realizing that was wrong. you just had to do what hookem said: take 10r + s = 117649, subtract the provided answers for s from both sides, and see if it made the big number divisible by 10</p>
<p>Hey, does anyone remember what was the answer for XYZ plane question? I had no idea how to get the answer. I think I just gussseed that X=1…;;=_= </p>
<p>And also for the question that asked : abs(x) =abs(y), what has to be true. I put x=y is it right?</p>
<p>I’m a junior, and I took the math II for the first time today. I omitted 9 and prob got like 5 wrong.
I’m taking BC so I didn’t remember anything on ALG II. (I should’ve studie more)
but the nice curb, will it still give me something around 750?
If I’m aiming for MIT or ivy leagues, should I just cancel my score and try it later again?
someone told me if I take it twice, it just looks bad, and someone else told me that if I do better than the first time, it looks good.</p>
<p>I don’t know what to do. Help me!</p>
<p>I skipped this problem (even though I think I know how to do it) because it’s pretty tedious. First, I believe you would use the given points to construct a 3d distance formula: root((x1-x2)^2 + (y1 - y2)^2 + (z1 - z2)^2). That gives you the length of the line. Now, imagine the diagonal as the hypotenuse of a right triangle. Use the given points to figure out the vertical and horizontal lengths, and solve for the other sides. I don’t remember what it asked for (maybe the area) but just use the information you get.</p>
<p>help123, i agree with x=y but don’t recall x=1</p>
<p>shinee, that’s mid 700s. don’t cancel. starting with your year, you’ll have the option of choosing which scores you want to have sent. for examples, you could take the SAT 4 times and 3 SATII’s 3 times each, but send only the top scores you earned. you probably shouldn’t take 12 sat tests though. anyway, that’s a great score.
math2
mean 644-650, 700 63%ile, 750 77%ile, and 800 90%ile</p>
<p>thanks for the reply otrebmu, but I thought the rule for being able to choose the scores that gets sent starts in March, and anything before doesn’t count. ?</p>
<p>so for the compounding problem, it won’t work if you just did (initial) x (1.052)^4?
ugh, that’s troublesome.</p>
<p>also, will the college board round up; say you miss 5 questions, will it automatically subtract 2 points?</p>
<p>no. you have to divide the rate by four. What you just did was something compounded annually for 4 years, instead of something compounded quarterly for 1 year.</p>