<p>The inverse was 0, #50 was 2log(cosx), vector was 4th quadrant, stand dev was only III, ax^2 +bx + C= -dx + e was a…</p>
<p>For the #50 question, I got 2log(cosx). Was that correct?</p>
<p>TI-84 Plus</p>
<p>It was my first time taking it but I thought it was actually pretty easy. There were 3 or so that I left blank and I probably missed 3 or so.</p>
<p>I expect a 750+ with a small chance of an 800 (unless the curve is generous).</p>
<h1>50 was 2logcosx without a doubt.</h1>
<p>The vector pointed downwards because the A vertor had a higher y value than the B.</p>
<p>Standard Deviation was only the multiply one.</p>
<p>ax^2 +bx + C= -dx + e, I put d because the E has no x term and could thus be added to the c. Actually I might’ve left it blank because I was unsure. Who knows? </p>
<p>Surface Area WAS 189 because to find the length of the middle one you had to visualize the prism in 3D and use Pythagoreans on the right triangle. It was out to be like root33…the width was just 8 like the others.</p>
<p>Inverse equation was 0</p>
<p>The origin one was the one that looked like tangent curves.</p>
<p>@ neohanyou yeah i also got 168 but it wasnt there, so I just guessed E. 182 im not even sure. This was a wierd hard test.</p>
<p>The K question was all reals expect k = 0</p>
<p>Oh yeah I remember that ^ I had that also. since it could not be 0 cuz then it would be undefined.</p>
<p>for the Maria question</p>
<p>I had (1.05) square t * A I’m not sure it was pretty hard.</p>
<p>shahdin, A(1.05)^t was correct.</p>
<p>@Shahdin</p>
<p>Maria question was (1.05)^t * A</p>
<p>Wouldn’t the answer to the limit question be no limit?</p>
<p>If you factor (x^2 -1) into (x-1)(x+1) , and the denominator is (x-1)</p>
<p>The denominator is still (x-1) so if you plug in 1, you get zero in the denominator which is a vertical asymptote.</p>
<p>I got 4 straight C’s for the last four problems. Anyone got that?</p>
<p>Was the Origin A or D</p>
<p>Was the ax^2 Bx= -dx </p>
<p>was it B?? </p>
<p>I think I got 1 or 2 wrong</p>
<p>at shahdin, yes, thanks for correcting my typo.
For #50, I picked the ans that has denominator = sinx-1. I can’t really remember it</p>
<p>I think #49 was E, and @Jonnw that doesn’t matter the limit still exists even if it’s not defined.</p>
<p>@jonww x-1 cancelled</p>
<p>x+1 was there on the numerator</p>
<p>1+1 =2 I think.</p>
<p>Didn’t take Math II today, but willing to help out.</p>
<p>I’m going to assume that the equation was (x^2 - 1)/(x-1) since you can’t factor out (x-1)^2 into (x+1)(x-1). If it is, solution is still similar.</p>
<p>When you factor it out, you have to cancel the like terms (Division!). In this case, (x-1). That will leave you with (x+1) as the equation that you will have to deal with.</p>
<p>@Shahdin the ax^2 Bx= -dx was A</p>
<p>I got 2 for the limit question?</p>
<p>@spratleyj What was #49? (The question)</p>
<p>@Esather Given what people were saying (limit goes to 1) it should be correct.</p>
<p>ax^2 + bx+c=dx+e –> ax^2 + (b-d)x + (c-e)=0. 2 real solns means that A is not 0. That’s my logic. Can anyone confirm this question?</p>