December SAT: Math

<p>miles20...i think i got 48...</p>

<p>jsmith do u remember if the answer D-E was the last choice</p>

<p>"does anyone remember the grid in that had a room 16X12 and it asked how many 2ft rug squares were needed to fill it? what was the answer?"
That could be the easiest problem, (12x16)/(2x2)=48</p>

<p>what is the highest I can get with a wrong grid ans and a wrong multiple choice answer. Anybody?:(</p>

<p>yeah i got 48 for the grid in one.</p>

<p>but are you sure it was all three. i think i got only two.</p>

<p>how did you solve that one.</p>

<p>no.. it was like the last 2nd...</p>

<p>A) A-B
B) B-C
C) C-D
D) D-E
E).. i believe this one might be.. A-E</p>

<p>ok thanks i got 48 too!</p>

<p>-2 was a 750 in November</p>

<p>I can get with a wrong grid ans and a wrong multiple choice answer. Anybody?</p>

<p>probably around 760</p>

<p>Why is 22 wrong for that divisible one?</p>

<p>"jsmith do u remember if the answer D-E was the last choice"</p>

<p>What was the question guys?</p>

<p>yeah.. see.. i got only 2... it was a and b... I and II.. but since the only way to include both I and II.. you have to HAVE I,II,III</p>

<p>the choices went like this</p>

<p>A) I
B) II
C) III
D) I and III
E) I and II and III</p>

<p>andrea - If you have the point (0,b) where a is 0, the radius is b, if you have the point (a, 0) where b is 0, the radius is a, if you have the point (a,b), the radius is srt a^2 + b^2</p>

<p>for that question i used lenght of an arc formula and i just gt pi as my answer</p>

<p>"yeah i got 48 for the grid in one.</p>

<p>but are you sure it was all three. i think i got only two.</p>

<p>how did you solve that one."</p>

<p>What question are you talking about?</p>

<p>HOW MANY TIMES?</p>

<p>Why is 22 not an answer for the divisible one?</p>

<p>Plze...</p>

<p>DId anyone get.. 2pi/3.. as an answer?</p>

<p>
[quote]
What question are you talking about??

[/quote]
</p>

<p>the one they just said. about the radius of the circle.</p>

<p>i remember getting 36 as an answer. i think it had an (x-3)(x-3) in it. does anyone remember that one.</p>

<p>
[quote]
for that question i used lenght of an arc formula and i just gt pi as my answer

[/quote]
</p>

<p>i did the circumference divided by three. whatever that was. but i dont think it was pi alone.</p>

<p>
[quote]
Why is 22 not an answer for the divisible one?

[/quote]
</p>

<p>i think it is.</p>

<p>the radius is 3 => P= 3.2pi
since the arc is 120 => Arc's P= 3.2pi/(360/120) = 2pi</p>

<p>dude. im pretty sure its 2 pi/3... cuz i remember from geometry.... </p>

<p>if the central angle = 120 degrees... the length of the arc equals the same!!!</p>

<p>Was 144 the answer to the problem where 2 was the median of like 70 integers and you had to find the smallest possible sum?</p>