<p>It said all 3 of the bottom lengths were 10, so the equilateral length (which is the other side of the triangle going up and to the left) was 10 and the base of the triangle was 10. The angle of the equilateral triangle is 60, so the angle between the two sides of 10 is 120 degrees. </p>
<p>Use law of cosines</p>
<p>c^2 = 100^2 + 100^2 - 2(100)(100)cos 120</p>
<p>cos 120 = -cos 60 = -1/2</p>
<p>Plug all that in, and you get 10 root 3 basically. Thats how I did it.</p>
<p>Blah, then it wasn't drawn to scale. How the did I miss that :(</p>
<p>draw an imaginary height in the middle of the equilateral. you know the every side is going to 10 so use pythag to find this height. then simply use pythag to find the unknown side. comes out to sqr root 300 or 10 sqr 3</p>
<p>It was 10 root 3. It was an isoceles, but why would it be radical 2? In a 30 60 90 triangle it is x, 2x, and xroot3. The hypotenuse was 10(i cut it up into 2 right triangles), so x was 5, and half the length was 5root3, double that would be 10root3.</p>
<p>Yeah I concede. This was my (faulty) logic:</p>
<p>I assumed I saw a right angle on the right triangle (don't ask me why). Then, seeing how the triangle was isosceles, I immediately applied the special 45 45 90 rule and moved on.</p>
<p>Whoops.</p>
<p>D-E is right</p>
<p>Anyone want to try compiling a list of the answers as someone did in the CR thread?</p>
<p>a+1, b+2 was the answer right. it couldnt be a b+1 since this line passed a b and had a higher slope then k. so a b+1 wouldnt work cause that would mean this line is undefined</p>
<p>. abs(x) - abs(y) = 10, x-y is none of the above (must be +, must be less than 100, could be zero)
. Circle centered at (0,0) and point (a,b) = all of the above, radius can be either a, b, or root (a^2 + b^2)
. function with .3 (box) = 2, since .32 = 8/25
. Transfer liquid from 1.5 gallon container = 7/30
. Range of millions of barrels = 15
. D = mode is less than average
. Every 3 and 5 min ring = 15 minutes after noon
. intersection (a,b) and (a+2,b+2), k had greater slope = point on k was (a+1, b+2)
. 5 combos of nickels, dimes, and quarters to get 30 cents
. ratio of p/k = 1/5, so n/r = 1/4 (letters may be off)
. Oil change = September 1st --- 3 months elapsed
. x, y, z on a number line = x is -6
. x = 1600 when yz = .05 (the one with the inequalities)
. x coordinate one less than y coordinate = 10/3
. 5-12-13 right triangle tangent to circle, CB = 8
. EBD equilateral triangle --- 10 root 3
. Ray + parabola, k = 4 (due to the slope of 2)
. 1:2:3:4 and 1200 phone calls = 480 calls were most
. 288 votes on pie chart
. x+x+x+x = x, so x = 0
. 27 = b^3, b = 3
. Probability of odd integers = 1/3, so even = 2/3
. Rectangular solid with sides 2 and 6 --- sum = 40
. Largest temp change = 4-6 pm
. Area of diagonal square = 18
With the help of beast69's previous post...feel free to add whatever you guys need, I actually posted this in what has become the CR thread on page 12.</p>
<p>guys for the last question i bubbled 3 by accident but then erased and changed it to 2. however, the erased bubble was still kinda dark. the new bubble was darker however. what do u guys think will happen</p>
<p>There was one that went like: If 1/3 of all the integers in a set are odd, what is the chance of choosing one that is even? I put 2/3, but it seems like there might be a trap.</p>
<p>integers have to be either odd or even, so 1 - (1/3) = must be 2/3</p>
<p>yeah, there are only two possible choices for integers, even or odd. so its just 1 - 1/3.</p>
<p>but what about zero? according to the blue book, it IS an integer.. but neither odd nor even.</p>
<p>i put 2/3 as well, but i was wondering about the possibility of a zero..</p>
<p>no, zero is even.</p>
<p>
[quote]
Zero is an even number. An integer n is called <em>even</em> if there exists
an integer m such that n = 2m, and <em>odd</em> if n+1 is even. From this,
it is clear that 0 = (2)(0) is even. The reason for this definition
is so that we have the property that every integer is either even or
odd.
[/quote]
</p>
<p>Yep, 0 is an even number. And it specified integers so they can't pull any weird stuff on us.</p>
<p>wow ur anwers make me scare cause i remember some and not others. The one with the equilateral triangle i remember someting wit a 9?? or am i just mixed up</p>
<p>ohhhh i didn't know it was even.. weird. alright thanks.</p>
<p>for that line one...was (a, b+1) even one of the choices?</p>
<p>Was it 22.5?</p>