January 2010 - Math Level 2

<p>Freaze, using the standard 44+=800 curve, you’d get a 740 with 5 wrong/6 blank.</p>

<p>btw: Can anyone explain how to do question 38 I think? It’s the one with f(x) = g(x)(x-r) (or something like this)?</p>

<p>I had no idea how to do it.</p>

<p>What was number 21? The probability question about Lake County and Louisiana.
I guessed 0.32. (I think it was B.)</p>

<p>^f(x) = g(x)(x-r)
Was it the one where if f(x) = 0 what is a possible value of x or something? Well either g(x) or (x-r) = 0 if f(x) = 0 therefore x would equal r because r-r = 0 OR g(x) would equal 0.</p>

<p>mabs, yes number 50 was E.</p>

<p>for number 38, the equation was f(x)=g(x)(x - 2) + r or something like that, and the question was what does r equal? </p>

<p>the answer was either C or D, whichever one was f(2) because (2-2) = 0, and 0 times g(x) = 0, therefore f(2) = r, so r must equal f(2)</p>

<p>Mabs, for #38. It was asking what value for f(x) would make f(x) = g(x)(x-2) + r = r. If you make x = 2, then the function would turn out to be f(2) = g(2)(0) - r, which would get rid of the g(x) making f(2) = r = r. I got stuck on that one too… it was the only one I had to skip I had no idea when I was taking it.</p>

<p>Stanfordpanda, #21 was the Indiana Lakeshore question. The answer was 0.32, nice guessing skills</p>

<p>OH ok I understand it now</p>

<p>During the test I just blanked. Never seen anything like that before.</p>

<p>i blanked on number 49 or 48, the one with the recursive series with even and odd numbers</p>

<p>how did you solve the lake county problem?</p>

<p>and why would it be f(2)? for instance, if g(x) was x^3 or something, then</p>

<p>x^3(x-2) = x^4 - 2x^3 + r</p>

<p>then f(2) wouldn’t give you r = r. whereas f(0) would. or am I missing something…</p>

<p>at above question ^</p>

<p>because its (x-2)g(x) if you have 2 for x it will automatically make it 0(g(x)) because of the order of operations (parentheses, then exponents, etc)</p>

<p>Silenceizsik, for #49, the answer was 19. because 5/7 is 0 remainder 5. 19/7 is 2 remainder 5. They both have the same remainder and are both odd. I blanked as well for like 30 seconds and suddenly it came.</p>

<p>Smellifer, for the example you give, x^4 - 2x^3 + r. If you make x = 2, it will still equal 0. 2^4 - 2(2^3) = 0. Thus r = r still.</p>

<p>And for the Lakeshore, Indiana question. You divided the number of people living in Lakeshore, Indiana by the number of people living in all the Lakeshores in US. You divided the number in the top left bow by the number in the top right box and got 0.32. The numbers in the bottom boxes were superfluous info. It was a pretty lame question…</p>

<p>What number was the regression one and the physics one?</p>

<p>guys this question:</p>

<p>a + (b/c)</p>

<hr>

<h2>f</h2>

<p>e</p>

<p>i rmb the choices being II = times f by 2 and III = times e by 2</p>

<p>now multipying e by 2 does not divide it in half</p>

<p>so i chose only II</p>

<p>anyone get the same as me?</p>

<p>Hm I thought it said III: divide e by 2
I could be wrong though.</p>

<p>anybody get the one with the equation x^2 +tx + c and asked what t equals? it was one of the two i omitted</p>

<p>answer is 16</p>

<p>use alpha + beta = -b/a
since alpha = 2 beta
so 3 alpha = -b /a</p>

<p>b = -24 and a =1</p>

<p>so 3 alpha = 24</p>

<p>alpha is 8 and beta is 16 </p>

<p>so answer is 16</p>

<p>now what about the </p>

<p>a + (b/c)</p>

<hr>

<h2>f</h2>

<p>e</p>

<p>question?</p>

<p>i swear that i rmb that choice III is multiply e by 2 not divide it by 2. I read it three times and so does my friend.</p>

<p>I agree. I don’t even think there were “e” at the bottom. I think there were some “g” under f.
Like this form</p>

<p>I think it was this form
a + (b/e)</p>

<hr>

<h2>f</h2>

<p>g</p>

<p>This also seems logicaly right a, b, e,f,g</p>

<p>So dividing e by 2 will not half the expression
May be our tests were little bit different.</p>

<p>tysm gilded!</p>

<p>anyone have a comment about the </p>

<p>a + (b/c)</p>

<hr>

<h2>f</h2>

<p>e</p>

<p>question?</p>