January 2010 - Math Level 2

<p>I think there was some question that asked you to find the maximum, I got 750? like you had to take the limit or something, does anyone know what I’m talking about. it was one of the earlier problems</p>

<p>mabsjenbu123,</p>

<p>i also got II and III, i’m not sure why everyone else said it was only III. im probably mistaken on number II because i was rushing like eveeryone else to complete the test. But, i’m not really sure, because im usually careful…idk.</p>

<p>also. i feel so ■■■■■■■■ not getting the f(x)=g(x)(x-2)+r thing right. it was the last question i was doing, and right at the last moment i realized f(2) would make g(x)(x-2) go away, leaving f(2)=f(2). but, time ran out, so i wasn’t able to change it. for number 50, did anyone get I and III, because i pretty much guessed.</p>

<p>The answer to the prime number is not ‘2 is a prime number’. The answer is '2(7)+1=15 which is not a prime number. Either way this is not maths, and due to the many question wording problems, I truly believe that the SAT is a fail. Bloody Americans…</p>

<p>Edit: I just remembered the question. It was ‘All prime numbers can be represented by the equation 2x+1 where x is an integer.’ It is 2 is a prime number because if you put 2 in the equation, x becomes 0.5 which is not an integer, therefore disproving the statement. Therefore, I failed. And I’m afraid that I won’t even get a 800 on maths. If a 750+ for both physics and maths, then will I blow my chances for MIT?</p>

<p>@a94wang
Do you remember what the question was asking for? I remember putting down 0 but I dont remember why…</p>

<p>ok so apparently the question for the halving question is </p>

<p>a + (b/c) / (e/f) </p>

<p>Does that help come up with a consensus?</p>

<p>it was what would make the equation true for all values of x, or something like that…</p>

<p>To help explain #49. It gave you a series where if n is odd, you divide it by 7 and take the remainder to get the nth term. They asked what would produce the same result as 5.
5/7 is 0 remainder 5.
19/7 is 2 remainder 5. Thus, 19 gives the same remainder as 5 would.</p>

<p>Also, mabs, I’m forgetting now. Did that halving question actually ask you to double it? Because I know the answer was II and III and I believe that’s the right expression but I forget the actual question.</p>

<p>@gilded</p>

<p>I think it asked to cut it in half</p>

<p>a + (b/c) all over (e/f)</p>

<p>does anyone remember all the answer choices?</p>

<p>it does actually double it, I tested with a few numbers lawl</p>

<p>and I put f(0) for that f(x)=g(x)(x-2)+r problem but is it actually f(2)? explain?</p>

<p>@smell</p>

<p>huh? The question was asking to halve it. Im still not sure what the correct answer is</p>

<p>Hmm how many wrong do you think will still qualify for an 800? It looks like the range has been around 4 - 6 questions wrong??</p>

<p>guys the answer to that question to halve it or whatever was II and III. it was: </p>

<p>a + (b/c)</p>

<hr>

<pre><code> f
</code></pre>

<hr>

<pre><code> e
</code></pre>

<p>just plug and numbers and you will see. multiplying f by 2 and dividing e by 2 will produce half of the original value.</p>

<p>6 questions at most if you’re lucky. You’d have a raw of 43 which might or might not make it.</p>

<p>mabsjenbu123, THAT’S WHAT I MEANT sorry</p>

<p>wait so was that trig question III or III and II.</p>

<p>Rtgrove, If you remember the question I might be able to help.</p>

<p>Hello,</p>

<p>I was slow on the test and left 6 blanks.
I thought it was pretty easy in general and prob think I did not get over 5 mistakes.</p>

<p>The first time I took it I made a lot of mistakes and left 4 blanks (I got 730)</p>

<p>Just wondering what do you think are my odds of getting over a 750.</p>

<p>Thanks</p>

<p>Is the consensus for the last one (50) E?</p>

<p>Freaze, it’s impossible to predict the curve sorry. In my opinion, I don’t think 6 skipped and 5 wrong would be over 750. That’s just my guess.</p>

<p>Mabs, I believe 50 was E. jansat thought so too.</p>