<p>Look at page 7 of this thread, we explained thoroughly, yes</p>
<p>yes i've read thru it. My question was, was 15 choice B</p>
<p>ya 15 was b</p>
<p>it went: 13, 15, 17, 19, 25</p>
<p>-Aaron</p>
<p>Does anyone know the usual scale for this test?</p>
<p>I obviously didn't study for this test and I omitted around 11 and guessed on way too many...</p>
<p>was the period of the abs value trig fucntion pie</p>
<p>2 pie / b</p>
<p>2 pie / 2</p>
<p>pie</p>
<p>It was pi/2</p>
<p>btw, I am almost positive that 15 was A.</p>
<p>I got pi b/c it was 2x and you divide by 2</p>
<p>The period of tan is pi, so pi/2 is new period.</p>
<p>yea, 2PI/b is for cos and sin, PI/b is for tan, so it's PI/2, not PI</p>
<p>ya it is pi/2 since tangent's normal period is pi.</p>
<p>I just graphed it, and zoomed in... then I saw where it hit x axis (0, pi/2,etc)</p>
<p>-Aaron</p>
<p>does anyone remember the question (and the answer) to the one that was a function and it said how many lines can be drawn that do not intersect the graph?</p>
<p>answer 2 there were two verticle asymtotes, and a Horizontal asymtote at 0 but (0,0) was defined.</p>
<p>alright and for the intercept question was the naswer 1/2 or 1/3?</p>
<p>intercept, you had to eliminate the parameter, solve for y, and find the value of b. I got -1/3 i think</p>
<p>i got 1/2, i guess that was the x-intercept. wat about the question that asked about x when lnx=e^-x?</p>
<p>I don't remember what I got for the 1/2 or -1/3 one.. can't remember the question for the life of me... but I did put two lines are possible to be drawn for the graph with two vertical asymptotes.</p>
<p>does anyone know when lnx=e^-x. i tried it on my calculator but i got a value that wasnt one of the choices.</p>
<p>I think i put 1 for the ln e^-x one</p>
<p>Oh jeeze, I remember doing that.. You had to be careful because if you solved it on your calculator you got the value for x, but the question asked for the value of ln(x)... I think I got 1.[something]</p>
<p>
[quote]
answer 2 there were two verticle asymtotes, and a Horizontal asymtote at 0 but (0,0) was defined.
[/quote]
</p>
<p>Aw man, it was defined at (0,0)? I put 3 =(.</p>