<p>xc + bc = c</p>
<p>there was on that looked like this
0 < 1/x < 1
0 < y < 1
find the greatest equation
i dont remember what i put i think d i got like 2.2 something</p>
<p>it was -m
i couldnt be reciprocal cz it didnt make a right angle</p>
<p>c/b question was
9/b and 3/c</p>
<p>So far so good I think… And yea I don’t remember the c/b = 1/3 problem -.-</p>
<p>Also, not that it matters, but maybe people would remember the question more if you put down k=104 (instead of c=104), cause I think that’s the variable they used.</p>
<p>The reciprocal is used for finding perpendicular lines. The intersection of the two lines was not perpendicular.</p>
<p>Well, it was -m because it was not a right triangle. If the two lines interested to form a right angle, then yes, it would be -1/m because the slopes of two perpendicular lines are negative inverses.</p>
<p>yrif it was x+b equals 1</p>
<p>x+b = 1. We didn’t need to find c.</p>
<p>@eurosport m was the slope of the right side, the other side of the triangle would have to be opposite of m, thus it was -m</p>
<p>It was what does x+b equal, and that would be 1.</p>
<p>This is because you factor c out of xc + bc = c… c(x +b) = c… therefore x+b must equal 1.</p>
<p>c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
20 people: I and II
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
Sum of first n+2 positive integers: (n+2)(n+3)/2
g(0): 6
Systems of equations with infinite solutions: c=104
X and Y: x+(1/y)
cx+cb=c: x+b is 1</p>
<p>@king1216,</p>
<p>I believe it was x + 1/y if you recalled that question correctly, since you would be adding two numbers greater than 1 if that were the case.</p>
<p>c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
20 people: I and II
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
Sum of first n+2 positive integers: (n+2)(n+3)/2
g(0): 6
Systems of equations with infinite solutions: k=104
x+b=: 1
0 < 1/x < 1, 0 < y < 1: x + 1/y</p>
<p>Greatest was x + 1/y I think</p>
<p>@king I said it was x+1/y</p>
<p>If anyone remembers the one about juniors and seniors, was the answer 2/3? Because I remember screwing up the variables and then fixing it.</p>
<p>bri1a4n yeah it was 2j to 3s because 3/5 were seniors.</p>
<p>whats possibility of 1 off (53 raw) being an 800</p>
<p>^2/3 is right</p>
<p>yeah i got 2/3 also</p>
<p>Ahh, I feel like an idiot, completely forgot that you should divide through by c.</p>
<p>c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
20 people: I and II
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
Sum of first n+2 positive integers: (n+2)(n+3)/2
g(0): 6
Systems of equations with infinite solutions: k=104
x+b=: 1
0 < 1/x < 1, 0 < y < 1: x + 1/y
Juniors and seniors: 2/3
Pentagon inside triangle: 7/9 x</p>
<p>nice yrif lol. i feel stupid also misreading the stupid chair problem lol</p>
<p>oh the grid problem with the square that was separated it was 1/8 of the total area</p>