<p>example like phone one:
1234567</p>
<p>1 and 2
2 and 3
3 and 4
4 and 5
5 and 6
6 and 7</p>
<p>maybe i’m just remembering the question wrong lol, but this is the same way i did it on the test. XD</p>
<p>eurosport there were 7 numbers 6 was the lowest choice lol</p>
<p>@ yR, you couldn’t use the exact permutation/combination formulae. I found that doing it visually was the best way.</p>
<p>@NerdosaurusRex yeah, I did 7!/6!</p>
<p>Now that I think about it, isn’t that question with the telephone a bit weird? Did it say what are the maximum number of possibilities or to assume all numbers were different? Because if they didn’t, what if you had two equal adjacent numbers? But either way, it’s probably 6 because that was the smallest possible choice.</p>
<p>Add c = 104 for the system of equations one.</p>
<p>oh if there were 7 numbers then nvm, but i did do the problem right then, I must have gotten 6, but answer my 3 circle question, how did you get 1 and not 1.5!</p>
<p>^ i got that too I V</p>
<p>c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
20 people: I and II
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
Sum of first n+2 positive integers: (n+2)(n+3)/2
g(0): 6
System of Equations: c = 104</p>
<p>c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
20 people: I and II
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
Sum of first n+2 positive integers: (n+2)(n+3)/2
g(0): 6
Systems of equations with infinite solutions: c=104</p>
<p>what is the systems of equations one? i dont remember that question.</p>
<p>can someone please refresh me on the c/b=1/3 problem?
thanks</p>
<p>It looks like I’m good. I just hope I didn’t do something stupid on one of the easier ones, or plugged in 104/4 = <em>26</em> rather than 104.</p>
<p>For the one w/ f(x)=a(x-c)^2… I got a=0.5 and c=2… so I evaluated the function based on that info… wasn’t it f(6) = 8?</p>
<p>@all4game,
The systems one was when they gave you two equations. It was like…x+2y=26 and then 4x + 8y = c. You had to find out what c was to make the system have an infinite number of solutions. So basically you needed to make both lines have the same equation.</p>
<p>Guys, correct me if I got the numbers in the equations wrong.</p>
<p>I V - yeah, that’s what I got.</p>
<p>it was 1/c= 3/b and asked for c/b</p>
<p>I also had 8…? lol and could someone explain the slope question for future reference.</p>
<p>SLOPE OF ONE SIDE IS M QUESTION: idk how it could be -m, becuase the graph was an X, so the negative slope was M , and the reciprocal of M is 1/-m am I correct?</p>
<p>HOW DID YOU GET ONE FOR THE THREE CIRCLES</p>
<p>if xc+bc=c and c isnt 0, what does c equal?</p>