June ACT Math Section

<p>does anyone have any idea what the answer to number 58 was? it was the question asking you to find the cos of the angle in a triangle with two sides of length 5</p>

<p>and also is the chair answer for sure not 110?</p>

<p>and is 1 wrong ever a 36?</p>

<p>was 58 (x^2-50)/50??</p>

<p>So…</p>

<p>First ACT I take and it’s one of the most ridiculous math sections I’ve ever seen. ;_;
My kind of luck…</p>

<p>This sounds bad. But math is bad for me…</p>

<p>what would -25 be? -30? -sobs-</p>

<p>58 was actually (x^2-50)/**-**50
so it was (50-x^2)/50</p>

<p>the answer to the chair one was for sure 160.</p>

<p>Depending on the curve -1 may be a 36</p>

<p>i don’t know about you guys, but i found the math section relatively easy. it may have been time consuming, but most problems took either 1 minute or less. in comparison to the april act, this was much harder, but that section was a cinch. </p>

<p>personally, i think i got -1 or -2. i’m sure people are just overreacting and will be fine. i remember after the April ACT, i felt horrible coming out and got a 34. i felt like i did perfect today so i’m hoping for a 36 :stuck_out_tongue: </p>

<p>good luck to all!</p>

<p>@jroth
I found it rather easy as well. But that might be biased as I just took my mathIIs last weak and those were… less than doable.</p>

<p>how did you figure out 160? i switched it last second to something else… but i almost put 160 just cuz it looked like 160 :/</p>

<p>“X-coordinate of midpoint: 10”</p>

<p>Does anyone remember this question specifically? It doesn’t sound familiar at all…</p>

<p>Does anyone remember the exact question in which the answer was -21 C?</p>

<p>I did something along the lines of 110-90=20
the using the opposite interior angles theorem (yeah… probably the wrong name for that) deduced that the angle I wanted was 180-20
which was 160
if that makes any sense at all.</p>

<p>@lacesea Yes, the question provided two coordinates and asked you to find the x-coordinate of the midpoint of the line between the two points. The answer was 10</p>

<p>Does anyone remember what the trig problems were ?</p>

<p>@lacesea
remember that question where they gave the two endpoints of a segment and then asked for the x-coord. of the midpoint?
it wasn’t hard.</p>

<p>@jroth94: When I saw what you wrote I was scared ****less thinking maybe I skipped over it. Then, suddenly, voil</p>

<p>@VT2015–</p>

<p>1) Isosceles triangle with two sides 5, one side X, unknown angle across from side X. Find the value of x if a^2= b^2 + c^2 - 2bccosA</p>

<p>2) Two right triangles, one lying inside of another. The most inner had one angle of 45 degrees, and the outer had an angle of 30 degrees. Find the length of the side across from those two angles if length of the base between the two angles was 10.</p>

<p>3) Right triangle with an angle equal to 67 degrees. Opposite side was x, adjacent side was 7.5. Find length of x.</p>

<p>That’s all I can remember</p>

<p>what was the answer to the pyramid one? I skippeD around and put a random answer because I didn’t gave time for that one. Today was my first time taking it and up until the last 5 because I was rushing but I think it was fine. it was a lot more straightfoward than sat math but I got a 700 on that so I guess well see</p>

<p>@ksh0815 Height of the pyramid= 14.</p>

<p>@ Jroth, I felt the same. April was insane, this was cake. </p>

<p>I’m figuring 4 i didn’t know, and 2 or 3 mistakes means -7, which is a 31 acording to aprils curve ( <a href=“http://talk.collegeconfidential.com/act-preparation/1152987-official-april-act-curve-table.html[/url]”>http://talk.collegeconfidential.com/act-preparation/1152987-official-april-act-curve-table.html&lt;/a&gt; ), which supposedly was the roughest around.</p>

<p>what was the answer choice for number 58?</p>

<p>The triangle one ? I put D</p>