June Math IIC

<p>I think you're looking at the math IC curve in PR because that one is a little more tighter than the math IIC..</p>

<p><a href="http://www.sparknotes.com/testprep/books/sat2/math2c/chapter2section4.rhtml%5B/url%5D"&gt;http://www.sparknotes.com/testprep/books/sat2/math2c/chapter2section4.rhtml&lt;/a&gt;&lt;/p>

<p>According to that table, I expect to get low 700s. Not bad considering I didn't prepare at ALL.</p>

<p>the answer for the pizza stuff is 92
cube function looks exactly like tan function so i did that right too :)
i skipped only the parametric equation and the period of the function . it seems i did all the others well . what is the minimum raw score that still gives you 800 ?</p>

<p>That table probably isn't accurate...look what I also found on sparknotes from the message boards:</p>

<p>"5+ curve means that a raw score of 45 out of 50 gives an 800. So...if you left exactly 5 blank, no wrong (because you get -1.25 for every wrong, -1 for every blank), you would get a closely borderline 800. For every test there's at least a 4+ curve, so any combinations of wrongs and blanks that yield 46= 800. the most generous curve ever given is 7+, which means 43=800, and that was probably a REALLY hard test; so 5+ is on the good side"</p>

<p>does that mean that since this test wasn't that hard then it might be a smaller curve?</p>

<p>What's the lowest I could expect for 3 omit and one wrong?</p>

<p>7/51 here for the glove question.</p>

<p>It was easy, but I effed up. If I had been wiser in my expenditure of time, I think I would've gotten at least a 780. Now, I don't think I even got 760.</p>

<p>@tux</p>

<p>I don't remember that problem, but I got that for something.</p>

<p>The pizza topping questions was 8 nCr 3 + 8 nCr 2 + 8 nCr 1, so it had to 92. It wasn't only 8 nCr 3 because the question did not mention that you had to pick 3 toppings from the 8. You could pick 1, 2, or 3.</p>

<p>There seems to be a lot of discussion about the cone problem. Can someone tell me what the actual question was? I don't remember, but I believe it asked for the depth that would decrease the volume of the cone by half. The cone had a depth of 4 and a radius of 2 or 1. It didn't mention anything about the cone being similar or the like. </p>

<p>The volume of a cone is 1/3(pi)r^2h. The way the cone was oriented 4 is actually the height.</p>

<p>4: 1/3(pi) (2^2) (4) = 16.75 inches cubed
2: 1/3 (pi) (2^2) (2) = 8.37 inches cubed</p>

<p>It should be 2. How does anything else work unless the question was worded differently for other people?</p>

<p>@tux</p>

<p>Again, you're right about the pizza problem.</p>

<p>The cone one you did wrong. You don't know the radius of the smaller one is 2. All you know is that h=2r.</p>

<p>So:</p>

<p>big cone: (2^2)(4)pi/3=16pi/3
small cone: 8pi/3=(1/3)pi(r^2)h
h=2r
8pi/3=(1/3)pi(r^2)(2r)
8pi/3=(2/3)pi(r^3)
solve for r:
4=r^3
r=1.587
h=3.17</p>

<p>No, the question specifically mentioned that the smaller cone is similar to the original cone (I remember it very clearly), so the answer is 3.2.</p>

<p>It said the cones were similar.</p>

<p>Same here. I could not be more positive that the new smaller cone was similar to the given cone. Solving for half the volume with radius to depth in a 1:2 ratio yields 1.6 as the new radius, thus 3.2 as the new depth.</p>

<p>i dont remember the 99-100 range problem what number was it?</p>

<p>@backslash</p>

<p>If you were referring to me, then look at the statement I said "h=2r" which is due to the cones being similar.</p>

<p>yeah, i dont remember this range problem...</p>

<p>did everyone have a range problem</p>

<p>hey afruf if the radius is kept at 2 and the heghit is 2 then the triangles formed can still be considered similar rite?</p>

<p>anybody remember 1,001</p>

<p>The q was something like:</p>

<p>"You have a set of data of 99 numbers. If you add a number to the set, then what CANNOT decrease?"</p>

<p>a. mean
b. median
c. range
d. (don't remember)
e. standard deviation</p>