<p>ugh you’re right. stupid stupid mistake. So far I have only 5 wrong. Assuming the curve is 43=800, i can still get a maximum of 1 more wrong.</p>
<p>cortana, u didnt skip any?</p>
<p>
Not what I got. I don’t think that was what the question actually said either. I got 18, because I got x-y or x+y or whatever to be 6, then it was 3(x-y) or 3(x+y). Anyone else?</p>
<p>@ cortana i think it was -5<x<0 dammit now im worried</p>
<p>does anyone remeber an inequality question or an answer like this ^^^</p>
<p>@ H3X… i got 6</p>
<p>guys, if i omitted 4, and pretty confident i got the rest right based on the posts can i scratch an 800?</p>
<p>also the trig question about tan >sinx or something was II and III right?</p>
<p>@steven nah i didn’t skip any. I finished with about 10 minutes to spare. I got the plane question legitimately wrong but the other 4 i made stupid mistakes. </p>
<p>@Westside it could be that. I just remember the x<0 part and then some negative, low number for the last part</p>
<p>@westsidestory:
The question was the range of “x” values for the inequality (absolute value of 2x+5)<5.</p>
<p>Now for my question: Does anyone remember a circular cylinder of height 4 and volume 250 in which the question asked the radius? I did that one approximately 7 times, but couldn’t find the answer by no means…
Wouldn’t it be that: Volume = Pi x (Radius)ˆ2 x height => Radius = sqrt(125pi/2)?
I’ve tried that several times, but no answers would match my calculations! Ack! 3D Geometry is so easy and I can’t fathom how I was able to miss such a straight forward and stupid question! Just praying for 760+ over here…</p>
<p>@brazbloke you would do 250=r^2pih so sqrt(250/pi/4)</p>
<p>i thought that problem was asking for which line is perpendicular. ■■■■…</p>
<p>there was another problem that hasnt been mentioned. it was like if y=f(x) is shifted up 1 left 3 and stretched vertically by a factor of 2, it becomes: [bunch of answer choices]</p>
<p>the question wasnt exactly like that, but i do remember a 2</p>
<p>brazbloke…125/4= (area of circle)
(area of circle)/pi=r^2
and then sqrt…</p>
<p>@grojos, yeah the answer was like D or E/ It was 2f(x+3)+1</p>
<p>Ya the 2k+1 question is all dependent on the wording. I thought it said if k is a prime number then 2k+1 is also a prime number. But if it said k is an integer if 2k+1 = a prime number. Although I think it was the former.</p>
<p>i definately remember a 2 being before f(x) and there were like 2 answer choices with that in it. it was one of the middle answer choices? oh and were those the right numbers?</p>
<p>i think it was D</p>
<p>grojos: i think the question was that, and so answer should be something like f(2(x+3)+1)?</p>
<p>@stevenydc the two would be on the outside</p>
<p>well what it said
is that every prime number can be expressed as 2k+1 where k is an integer.</p>
<p>Oh God! Now I see my mistake! Sorry, I have to eat some arsenic and will be back quite soon…</p>
<p>But first, what about the one of f(x)=g(x+2)(x) + r, for every “x” one? How did you guys solve that? Random values guessing?</p>
<p>@brazbloke it was screaming for a remainder theorem application. im glad i read barrons before this, i never learned that theorem</p>