<p>I just do them all on my calculator, which btw, is reaaaly helpful. Those of you who can, google TI calculator MathOS program, and transfer it to your calc. Literally the best thing in the world, and with it I can finish the Barrons test with like 5-8 min left to try the trickier problems.</p>
<p>educationOD i will do that… you are a hero. and i just did a Mcgraw hill test. only 2 wrong… How is the difficulty on that compared to the actual exam? I feel much better lolz. and i officially hate sparknotes. and i got the test from the mcgraw hill 15 subject tests.</p>
<p>@NspiredOne No problem! And I think only 2 wrong on any test puts you in a good position. I still get like 3 wrong on the Barrons tests, and got 2 wrong 1 skip on the released test (calculator was in radians mode… ) </p>
<p>@girlrockingguna Haha, I think my 3D cube just lacks the shading. :P</p>
<p>@PCwizCube Yep, that’s the one! If you have room on your calc, you can also get the Formulas program, which may or may not come on handy if you already have the MathOS program.</p>
<p>Edit: I know right! I found this the other day and literally smiled at my calculator for a good 2 minutes…</p>
<p>I took 2 Barrons practice tests. First time was a 680 and second was a 730. Does anyone have an approximate conversion to actual SAT II Math scores since Barrons is supposed to be harder?</p>
<p>They’re in Chapter 8, just before the first test, I think.
Yeah they’re really helpful, especially QUADFORM ; w;</p>
<p>So Sparknotes is relatively accurate (but I think it was slightly easier) and Barron’s is harder?
Does anyone know a general sort of conversion scale from Barron’s to the real thing?</p>
<p>@all the people above- take a blue book test to see your score. Add/subtract 20 points from that to get your estimated scores. I made low 700s/high 600s on the Barrons test and managed to make a (low) 800 on the practice test from CB… but it all depends on the test itself imo. @Qwerty Nerd: Even: f(-x) –> f(x)
Odd: f(-x) –> -f(x)
Also, even = symmetric to y axis, odd = symmetric about origin (a,b) –> (-a,-b)</p>
<p>@QwertyNerd:
Even functions: they are symmetric across the y-axis, so flipping the graph across the y-axis (i.e. changing the sign of x) will get you the same graph.
f(x) = f(–x).</p>
<p>Odd functions: they are symmetric across the origin, so if you flip the signs of both x and y, you will get the same graph.
–f(x) = f(–x)</p>
<p>To check, do the above with whatever equation you are trying to figure out. For example:
f(x) = x^2 is a parabola, which we already know is an even function. To check if it’s an even function, remember f(x) = f(–x).</p>
<p>f(x) = x^2
and f(–x) = (–x)^2 = x^2</p>
<p>So f(x) = f(–x), and you have just confirmed that f(x) = x^2 is even.</p>
<ol>
<li> A two-sided coin is flipped four times. Given that the coin landed heads up more than twice, what is the probability that it landed heads up all four times?</li>
</ol>
<p>Sparknotes has this complicated answer explanation. ;/ The answer is 1/5 btw.</p>
<p>@feedback411. So this question deals with combinatorics. If there are more than 2 heads, that means there are either 3 or 4, and therefore either 1 or 0 tails respectively. The number of ways to choose 1 tail out of the 4 flips are 4 choose 1 = 4. The number of ways to get all heads is just 1. So, the answer is 1/(1+4) = 1/5.</p>
<p>^ I believe you only have to know the period for a function in the form y=atrig(bx+c) and the period would be normal period of that particular trig function over b. For sine and cosine the normal period is 2pi. and for tan its pi.</p>