<p>I cannot figure this one out... can you help me???</p>
<p>Solve.</p>
<p>log (base 3) 2x^2 - log (base 3) (5x-9) = 1</p>
<p>any ideas??</p>
<p>I cannot figure this one out... can you help me???</p>
<p>Solve.</p>
<p>log (base 3) 2x^2 - log (base 3) (5x-9) = 1</p>
<p>any ideas??</p>
<p>log (base 3) (2x^2)/(5x-9) = 1, meaning
3^1 = (2x^2)/(5x-9), so
3 = (2x^2)/(5x-9), thus
15x-27 = 2x^2,
0 = 2x^2-15x+27
0 = (x-3)(2x-9)</p>
<p>So it's either 3 or 9/2.</p>
<p>I'm doing this in class now too :) Exactly as Flippy said.</p>
<p>What kind of math is this? Algebra 2? Pre Cal?</p>
<p>i was going to ask that too.. Is it PreCal?</p>