<p>Crap crap crap. Alrite thanks.</p>
<p>telephone probabilities:</p>
<p>1/3 of calls are “L” ones. if you receive an “L” first, the second one must be an “S” one in order for you to receive one of each type. the probability for this is 1/3*2/3 = 2/9</p>
<p>2/3 of calls are “S” ones. If you receive one of these first the second must be an “L” one in order for you to receive one of each type. The probability for this is 2/3*1/3=2/9</p>
<p>Thus, 4/9 pairs of calls will be SL ones.</p>
<p>you could also draw a matrix thing and pair them up, and then count the SL ones. This is closer to the way I thought about it.</p>
<p>…S…S…L
S SS SS SL
S SS SS SL
L LS LS LL</p>
<p>@ TheMathNerd</p>
<p>I think emadwilliam multiplied for each possibility and then added them because it can either be international/local or local/international. Maybe it is 4/9, but I’m not sure.</p>
<p>Guys, the compound interest problem is definitely the answer starting with 47 (can’t remember it that well). I took a practice test on Sparknotes just yesterday and there was a compound interest problem just like that one. I answered the question by doing the (original number)*(1.0whateverpercentinterest)^numberofyears thing, and it was right.</p>
<p>ughhh now I am so confused!
& @TheMathNerd, nobody here got that</p>
<p>@ TheMathNerd: What I did was:
(1/3 * 2/3) + (2/3 * 1/3) = 4/9</p>
<p>P.S. you can sum up probabilities if you want the probability that either p1 OR p2 occur… You only multiply when you want both p1 AND p2 to occur…</p>
<p>Do you get it?</p>
<p>fledging - </p>
<p>wikipedia says its:</p>
<p>P(1-r/n)^nt</p>
<p>n=number of times its compounded (quarterly means 4)
r = the rate (5.3% or .053)
t = the total time (1 year)</p>
<p>the box was 96, yes.</p>
<p>The question said that it was compounded quarterly!
Your equation is this: f(x)=(Initial Value)(1+.052)^(t/4).</p>
<p>I did:
$3500 * (1 + 0.052/4)^4</p>
<p>Is that correct?</p>
<p>Yes. </p>
<p>10char</p>
<p>^don’t think most people got that</p>
<p>probability is 4/9</p>
<p>ALL PROBABILITIES ADD UP TO 1</p>
<p>Local + Long =1/3 x 2/3 = 2/9
Long + Local = 2/3 x 1/3 = 2/9
Long Long = 2/3 x 2/3 =4/9
local local = 1/3 x 1/3 = 1/9
SUM OF THEM = 1 … Add the 2/9 + 2/9 = 4/9</p>
<p>^oh god, if you’re right… -sigh- there goes my dream of getting a good mark</p>
<p>and yes emadwilliam</p>
<p>Another way to solve the probability is
1 - (sum of LOCAL/LOCAL and LONG LONG probabilities)
Because if you dont get 2 of the same type, you get one long one local and vice versa </p>
<p>1 - 5/9 = 4/9</p>
<p>can anyone predict what the curve’s going to be like? or can you link me to past curves please? thanks!</p>
<p>Ugh this test killed me. Omitted like 13. I always feel really confident until it gets to the 30s. I’m hoping for a 700 at least.</p>
<p>@austrianpog: Use this (average) conversion table: [SparkNotes:</a> SAT Subject Test: Math Level 2: Math IIC Scoring](<a href=“SparkNotes: Today's Most Popular Study Guides”>SparkNotes: Today's Most Popular Study Guides)</p>
<p>^ thank you emadwilliam!</p>