<p>@Illimani - i’d say at least 750 for cornell</p>
<p>^illimani are you an 8th grader??? I have no idea then. Btw, 750+ for cornell</p>
<p>Anyone want to mention more questions so I can check lol.</p>
<p>For the area of the squares with coordinates doubled, did anyone get 4?</p>
<p>YEPP I got 4 too :)</p>
<p>aw shoot i got 1/2 haha no idea what happened there</p>
<p>Ya x4 is right because you change distances you can even check it diagonal of one is 8sqrt2 and other 16sqrt2. Therefore areas are 128 and 32.</p>
<p>I agree with somekid after my post. answer was 11 for vector because of law of cosinses for 130 degrees, 4, 8. Or use vector addition and find the norm so sqrt (10^2 + 3^2)</p>
<p>Pi/2 for the area if the triangle. </p>
<p>What was the answer to the question that mentioned the angle between the two vector?</p>
<p>yeap pi/2 for the triangle</p>
<p>i got like 8 for the vector one not sure though</p>
<p>pi/2? what was the q</p>
<p>@Whatdoyouthink
lol I’m actually a senior which is kinda sad (cause I think I did terrible).
I also got 11 for the vector</p>
<p>The question showed a triangle in the first quadrant. Not sure what the function was. But the height of the maximum point was 2 and the zero of the function was pi/2.
A=1/2<em>2</em>pi/2</p>
<p>For the chemistry one or something where you had to find m, did anyone get 2?</p>
<p>@Whatdoyouthink
lol I’m actually a senior which is kinda sad (cause I think I did terrible).
I also got 11 for the vector</p>
<p>What did you guys get for the period of trignometric function of abs(blah)? I got 2pie.</p>
<p>I got 2pi. ^</p>
<p>did u w=2p/t?</p>
<p>Woah. I got 4pi
F(x)=cos .5x
T= 2pi/w
= 2pi/.5 = 4pi</p>
<p>It was the abs value though, so it did some shifty thing to the graph. Graphed on my calculator. ^</p>
<p>Agreed with IHateYouVergil, graph showed that they were 2pie apart</p>
<p>alright lets stop discussing … already got like 4-5 wrong… haha gets me too worried, but i cant resist not checking this thread</p>