<p>This test was weird, it started of really easy. Then towards the end, some very tricky questions.</p>
<p>How do you calculate r for the sphere, with an inscribed cube with side S?</p>
<p>oh maybe i put 2.6 then…is that right?</p>
<p>"That reminds me, was the “Which of the following, for x > 2, is NEVER an integer:” x / (x-1) "
Yes, I believe so.</p>
<p>what did you put for the equation and then question that said what is the largest x that can make fx = 5</p>
<p>the f(x)=5 was some simple quadratic wasn’t it? I think of the two roots, one was negative and the other was the answer.</p>
<p>hmmm i don’t remember…i just plugged in the x values and saw which one (the biggest x value) made the equation equal 5…
it wasn’t about roots…
i circled the one that made the equation = 5.01</p>
<p>I solved the equation and got something like (a positive integer) + sq.rt.something. Sorry don’t remember anything else.</p>
<p>wat about the pt that lies outside the cirlce…the pt was (2,1)</p>
<p>(x-2)^2 + (y+1)^2=4</p>
<p>does that look familar</p>
<p>abatis…do you remember if you circled e…or the biggest number there…if you did square root stuff…make sense if i got 5.01</p>
<p>was the population one “C”? cause I guessed that
as for the roots I put 4… since it asked for f(x) and g(X) each with 2 distinct roots and f(x) COULD NOT equal g(x). (x-2)(x-3) = f(x) and (x+2)(x+3) = g(x) multiply them = 4 zeroes (thats how i did it at least…)
I felt that was WAY harder than all of the practice tests I took (barrons/sparknoets/pr/even their own “official practice tests”) I guessed on two and didnt know 3.
For the cube and sphere one isnt that just (s * sqrt 2 )/2 cause the 1/2 the diaganol of the square is the radius of the sphere. the 2 triangles that make up the square are a 45 45 90 triangle thus s, s, s sqrt 2 then s sqrt 2 /2</p>
<p>"wat about the pt that lies outside the cirlce…the pt was (2,1)</p>
<p>(x-2)^2 + (y+1)^2=4</p>
<p>does that look familar "
The answer to that was either D or E.</p>
<p>I think the point was something else. All the points were (2,y) so you could ignore the first part. Then whichever y value squared was bigger than the radius squared was the answer. I think. lol.</p>
<p>Ahhh, that makes sense. I thought that the given values were the means, not the specific scores given by the judges. </p>
<p>“That reminds me, was the “Which of the following, for x > 2, is NEVER an integer:” x / (x-1)” Yes, i got that too.</p>
<p>“How do you calculate r for the sphere, with an inscribed cube with side S?”
You had to basically find the distnace from one corner of the cube to the opposite corner, and divide that answer by two. It involved making 2 triangles and solving for the hypotenuse.</p>
<p>@ abatis which answer?</p>
<p>What was the tan question? With an answer choice of like 1/a^2.</p>
<p>@Caramel:I don’t remember. Sorry.</p>
<p>Legend: If tan x = a, then what is sec^2 x</p>
<p>@ the legend it was uhh 1 + a^2</p>
<p>just plug in a number</p>
<p>“For the cube and sphere one isnt that just (s * sqrt 2 )/2 cause the 1/2 the diaganol of the square is the radius of the sphere. the 2 triangles that make up the square are a 45 45 90 triangle thus s, s, s sqrt 2 then s sqrt 2 /2”</p>
<p>The answer to this one should be (s*sq.rt.3)/2</p>