October 2009 SAT Math

<p>Does anyone want to figure out the circles/radius problem right now if I give it to you?</p>

<p>There are three circles: Circle 1, Circle 2, and Circle 3. The sums of the areas of these circles is Pi. Circle 2 has a radius that is 1/2 the radius of Circle 1. Circle 3 has a radius that is 1/3 the radius of Circle 1. What is the radius of Circle 1?</p>

<p>…Is that correct?</p>

<p>yeh but the red line for example is joiningg the verticees of 2 adjacent sides , and the question was non adjacent</p>

<p>the answer was 6/7 to the pi question.</p>

<p>For the circle question was 7/6 an answer?</p>

<p>Because I knew I put that or 6/7.</p>

<p>I think I put C.</p>

<p>Help?</p>

<p>corey but the red line in ur figure is joining the veticees of 2 adjacent sides , and the question was non-adjacent</p>

<p>for the scatterplot… the answers A guys… I got that wrong too… if you put it into your calculator with the same axis ranges as the scatterplot, you will see a line that has a similar slope to that of the scatterplot trend. I figured that out as I walked out of the classroom.</p>

<p>As for the 1000 numbers… it said all positive even numbers NOT divisible by 3?
I put 333. I hope thats right. :confused: I subtracted the total even numbers in that range by the total number of integers divided by 3… or something like that.</p>

<p>Anyway, ill be happy with a 760 or so. 2100+ and im set.</p>

<p>No it’s not there is a vertice between them…</p>

<p><a href=“http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg[/url]”>http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg&lt;/a&gt;&lt;/p&gt;

<p>@ sqdw,
to do , i said radius for 1 ,2, 3 was 6x,3x,2x respectively
pi= pi x^2( 36+9+4)
1=X^2(49)
x=1/7
and circle 1 is 6x is its 6/7</p>

<p>at blackrose, the scatterplot was slope was 5x and y intercept was like 20, just do delty/delt x, its clear the slope was 5</p>

<p>^okay, well i hope you’re right because thats what i put lol.</p>

<p>richard nonadjacent means it doesnt share the same vertex, i looked it up its 9</p>

<p>Thanks Whatisthis1.
Doesn’t make a difference, but I messed up because I assumed that the 4 sides of the rectangular cube was equal, and thought that the the top and bottom of the cube were equal too.</p>

<p>But, it doesn’t matter now, I got it right.</p>

<p>X < Z - Y</p>

<p>for triangle one?</p>

<p>Circle Question:</p>

<p>Pi * R1^2 + Pi * (R1/2) ^2 + Pi * (R1/3)^2 = Pi
R1^2 + (R1^2)/4 + (R1^2)/9 = 1
36<em>R1^2 + 9</em>R1^2 + 4<em>R1^2 = 36
49</em>R1^2 = 36
R1^2 = 36/49
R1 = 6/7 </p>

<p>Hexagon Question:</p>

<p>n(n-3)/2
6(6-3)/2 = 9</p>

<p>1) did you have a question with a pyramid where it gives you the formula to find the volume of a pyramid??</p>

<p>2) did you have a question with musicians and flag beareres and you had to find the total number of people</p>

<p>3) did you have a really easy problem like square root of (x-2) = 10 and you had to solve</p>

<p>and for people who had an experimental in math!?!? i think 7 was the experimental section!! any clues??
i had 3,4,7, and 9 as math and i wanna know which one was experimental</p>

<p>anyone with the answer to the integers less than 1000 not divisible by 3</p>

<p>^it was 666…but i put 667 :frowning: hate myself</p>

<p>I had this Sqrt(x-2) = 10</p>

<p>x = 102</p>

<p>@mmwhatyousay: I didn’t have the second one on your list but I had all the others.</p>

<p>I had an experimental writing section.</p>

<p>X = 105…</p>

<p>root (x - 5) = 100 ?</p>